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PIO(A1ow <br />'S1 f-' W. <br />MOUND DESIGN WORKSHEET <br />(Fnr Rtnwa un to 1200 ar)d) <br />A. FLOW V"w <br />Estimated 700 gpd (seepages D-7 or I-3, 4, 5) <br />or measured ' gpd x 1.5 = <br />B. SEPTIC TANK LIQUID VOLUMES <br />gallons (see pages C-3 or C-5) <br />C. SOILS (refer to site evaluation) <br />1. Depth to restricting layer = " ' inches <br />2. Depth of percolation tests = 1 inches <br />3. Percolation rate i > • V mpi <br />4. Land slope % <br />Fstimrod Sewste Flows in Geums ps day <br />(9" <br />Nwnber <br />Of <br />dim 1 <br />Type u <br />Type ut <br />7a <br />1ledrmms <br />v <br />2 <br />3W <br />225 <br />160 <br />3 <br />450 <br />300 <br />218 <br />soa <br />d <br />600 <br />375 <br />256 <br />a■ <br />•�• <br />S <br />730 <br />450 <br />294 <br />6 <br />900 <br />523 <br />332 <br />TEL <br />7 <br />1030 <br />600 <br />370 <br />v <br />6 <br />1200 <br />I 67S <br />1 606 <br />r�W <br />SWk T--h Cep w" I• a-N w <br />N-N-4 <br />lhn-.L.j•.d <br />Lpu._a-.pady-gym <br />iWJr. 9 <br />C..I.•c.ty <br />'mt.", J..;w 1 <br />2 a k s <br />730 <br />112S <br />3 W • <br />Ion <br />13W <br />s W 6 <br />file <br />2230 <br />7.8wo <br />3" <br />311� <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required arez, of rock <br />layer: Daily Flow x 0.83 = a. <br />�c-�y and x 0.83 sq. ft./gpd <br />2. Select width of rock layer (10 feet or less) _ c ft. <br />3. Length of rock layer = Area + Width = <br />a -),:� sq. ft. + / o ft. = a 7 ft. <br />E. ROCK VOLUME <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />a23sq. ft. x4!ift. -2�cu. ft. <br />2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />cu. ft. + 27 = ) I cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />1 cu. yd. x 1.4 ton/cu. yd. = J-,:� tons. <br />F. ADSORPTION WIDTH 1 P k1 rr1 <br />1. Percola 'on rate in top 12 inches of soil is mpi <br />2. Select allowable soil loading rate from table on page E-; <br />- y-� gpd/ ft2 <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft" by allowable soil loading rate; <br />1.20 gpd/fe+-4-CgPd/ft2= D.(, I <br />Check this value on page E-16. <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />/o ft = ",'2 ft <br />Rock Bed <br />J•I•I•I•NI J•J•I•I I•I•J•J•J <br />F �• <br />J�I~l,I J•I}jyIp Ill S10 ft <br />1-- Length <br />Abwrpllm wroth sbrRIITbbk <br />tale.Ir I RM <br />iw Mil"" p� <br />kch IN) <br />soil 7iaare <br />Gala. <br />pa der per <br />"An few <br />OaWef <br />Ahempli- wi46 <br />r �kW <br />IrWO dye I~ 1 <br />CWM SMd <br />--- <br />- <br />&I IDS <br />Saari <br />1.30 <br />1.00 <br />01 SI <br />Fs Sm• <br />0.60 <br />2W <br />6bS <br />b <br />irdr Law <br />079 <br />1.32 <br />16 b 30 <br />l ear <br />Q60 <br />21.00 <br />31 b 45 <br />Sik law <br />0.50 <br />2.40 <br />"to 60 <br />Ck lases <br />0.43 <br />2.67 <br />60 b 120 <br />Clq <br />014 <br />S.W <br />Slows AN <br />clay <br />- <br />- <br />I20••• <br />