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END PERFORATION OF A PERFORATED LATEW <br />PRE55URE D1STR1i311T1ON SYSTEM <br />1. Select number of perforated laterals ) <br />2. Select perforation spacing = - 3 _ feet <br />3. Since perforations should not be placed closer than 1 ft. to <br />the edge of the rock layer (see diagram), subtract 2 ft. from <br />the rock layer length. <br />.wq0 -ft. -3�' feet <br />Rock layer length <br />4. Determine the number of spaces between perforations. <br />Divide the length above by perforation spacing and round <br />down to nearest whole number. <br />.0 Gross [aver <br />Tapsalt <br />• LoarySand �Yqr <br />Loyer of Geoleellle Fabric r-- <br />Inch layer of hay or 11row <br />` '' <br />� <br />e•"� �.' 1' <br />ud rorin paper) <br />I <br />Drilled Nar h. <br />• <br />t <br />e/4` PIU4 <br />.. 11 Into C. pyNear hP <br />1 <br />r i '•,]-Al Least Ix• to E• <br />a pleld Rock <br />of Rack Layor <br />. <br />-Per lorollalu Located of <br />. Clean Sand Layer <br />Balrarrl of Lateral <br />`- Original Sall Properly Scarlrie4 <br />Before Plaeing Sand Layer <br />TABLE Or. PERFORATION DISCHARGES IN G <br />IHead Perforation diameter (inches) <br />I I "/" I '/e <br />Length perf. spacing -._---ft, as�ft. saces <br />1.04 <br />1.5 <br />0.56 <br />0,69 <br />0.74 <br />0.90 <br />•S <br />03) {#2) <br />2.Ob <br />2.5. <br />0.80 <br />0.89 <br />1A4 <br />1.17 <br />5. Number of perforations is equal to one plus the number of <br />3.0 <br />0.98 <br />1.28 <br />perforation spaces , <br />4.0 <br />5.0 <br />1.13 <br />1.26 <br />1.47 <br />1.65 <br />nUse 1.0 foot of head for residential systems. <br />spaces -1- I = 1_ perforations per lateral bUsa2.0 feet of head for otltereslablishments <br />6. Multiply perforations per lateral by number of laterals to <br />get total number of perforations. <br />x � _ra - perforations <br />lateral s pt:rfs/lau•ral - <br />7. Determine required flow rate by multiplying <br />number of perforations by flow per perforation <br />4(9 <br />perfs x gPot/perf gplll. <br />Table 2 <br />Maximum ollowobte numher or gdater inch per-forrrlians per <br />lateral to guaraniLV c 1 0 % IMschurRa varialian <br />perforallnnspeeing <br />(r�wp <br />1,25 IIICtl <br />1.5 inch <br />i.{} in <br />2.5 <br />14 <br />18 <br />28 <br />3.0 <br />13 <br />17 <br />26 <br />3.3• <br />12 <br />16 <br />25 <br />4.0 <br />11 <br />15 <br />23 <br />5.0 <br />10 <br />14 <br />22 <br />8. If laterals are connected to header pipe as shown on upper <br />example, select minimum required lateral diameter from <br />table 2; enter table with perforation spacing and number <br />of perforations per lateral. Select minimum diameter for <br />perforated lateral w _ 1 rq inches <br />9. If perforated lateral system is attached to manifold pipe near <br />the center, as in lower example, perforated lateral length and <br />number of perforations per lateral will be approximately one <br />half of that in # 6. Using these values, select minimum <br />diameter for perforated lateral from table 2 <br />perforated lateral inches <br />..ro,q.r�r� isrriwrM,rrw",',c�1wr <br />.-ems,- <br />tm_ <br />