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1. If landslope is 2.9 percent or less, basal width ir.ciudes both the <br />upslope and downslope dike widths, <br />2. <br />Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation /. O feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slope Difference 3 yl <br />lo % + 100 = to feet <br />c. Add depth of clean sand depth of clean sand for I. <br />separation at upslope edge (2a) to depth of rock layer to ..... <br />rock depth and the depth of cover to find the total mound �- <br />height at upslope edge of rock layer; <br />/. O ft + 1 ft + 1 ft = 3.0 feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of ? .`) o <br />e. Multiply mice multiplier by upslope mound height <br />to get upslope dike %idth: -I, j x i I feet <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height •c + . Z = feet <br />g. Enter table on page E-18 with landslope and downslope <br />dike ratio. Select dike multiplier of � . ? :�, _ <br />h. Multiply dike multiplier by downslope mound height <br />to get do slope dike width: 2— x y 3 : = I q feet •'� ��►31 •►'+ "� <br />i. Minin. 3m mound width is the sum of upslope dike <br />width plus rock layer width plus downslope dike width; <br />I I ft + _�U ft + _..c; ft _ Lj� feet <br />j. Subtract ! ium width G.i from the Absorption <br />width F 4 ' Additional Dox-. nclope required for <br />Absc 'ption <br />— - it - _'�ft = =Lj- <br />feet iPw <br />k. Add the Additional Downslope required for Absorpt;') <br />to the downslope dike width and recalulate the Total <br />Mound Width which is is the sum of uns;ope dike <br />width plus rock layer %:idth plus downslope dike % iath <br />—I j_ ft + _J_� ft +_ e,o_ft = --- feet <br />feet <br />1. Total mound length is the sum o► upslope dike width <br />plus rock layer length plus upslope dike idth; <br />�-- Tou! Length <br />/off <br />L)u,A 11? o1w PS 01V <br />31 ,1 SI 61 -1 ]1 ,1 it 61 7 61 <br />0 3.0 60 1 6o :U 17 ,P 5U 6U7 60 <br />417 <br />3.61 76 62S 'ss ♦ in: i>• na <br />S )S) S00 667 857 1'177 ��i ))i il❑ ,62 SIV i'1 <br />6 366 i2A 7.16 v' !21': 25i 3V 3!li 6A 4•3 i,l <br />?h0 7wi :37) 2:• 3:2 3713 623 ,"• 5 : 3 <br />6 3.vi ..n 6.33 :154 W '.:: 3'P 1 i7 { 16 ♦ :• t u <br />V l:! .J1 i314 2N )4i 3NI : 463 <br />,y n•.' .':0 tiUU :''3 :tl 2v. ;33 17i ,:: ,:.i <br />12 4 6v 7 69 214i 4, " : 21 2 7J 3 12 3 ,v 3 6c! 406 <br />