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1993-12-10 Septic System Design Report
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1993-12-10 Septic System Design Report
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Last modified
8/20/2025 10:07:31 AM
Creation date
8/20/2025 10:03:17 AM
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x Address Old
House Number
2875
Street Name
Deer Run
Street Type
Trail
Address
2875 Deer Run Trail
PIN
0411723240009
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MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated 0 gpd (see pages D-7 or I-3, 4, 5) <br />or measured -- gpd x 1.5 = _ - <br />B. SEPTIC TANK LIQUID VOLM IES <br />j-ta,SO4 l -Too gallons (see pa jes C-3 or C-5) <br />C. SOILS (refer to site evaluation) <br />1. Depth to restricting layer = -3 c.l'fv �io inches <br />2. Depth of percolation tests inches <br />3. Percolation rate L. 9 mpi <br />4. Land slope % <br />Eaitnxk4 Seurage Flow in Gallons pa day <br />(aw) <br />Number <br />or <br />Type I <br />Type 11 <br />Type III <br />Iledraolns <br />i V <br />2 <br />300 <br />225 <br />ISO <br />3 <br />450 <br />300 <br />218 <br />♦ <br />600 <br />375 <br />256 <br />l6n. <br />.r.p <br />5 <br />6 <br />750 <br />900 <br />450 <br />525 <br />294 <br />332 <br />L <br />7 <br />>f <br />1060 <br />12W <br />600 <br />675 <br />370 <br />409 <br />to <br />.��. <br />tiydc T•d C.p.. a:� M a.14... <br />lie*s &mb.W d,.w..l <br />2.r Yr <br />750 <br />1125 <br />3 ar a <br />1010 <br />15W <br />♦ a 6 <br />131D <br />2250 <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: Daily Flow x 0.83 = <br />f)SO gpd x 0.83 sq. f t. / gpd = C,a .� sq. f t.-H o'5 (oY 4 <br />2. Select width of rock layer (10 feet or less) _ / 0 ft. <br />3. Length of rock layer = Area + Width = <br />v Ll sq. ft. + i p ft. = (, i� ft. Rock Bed <br />♦;t 1.,.. �•,..��l�ti.•. ti tis <br />E. ROCK VOLUME `-�f•. ng f.f.'.f.'.�.• <br />Length <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />4z-j�a sq. ft. x L. . ft. = 21.E cu. ft. <br />2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />r) I V cu. ft. + 27 = -a 1) cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />III cu. yd. x 1.4 ton/cu. yd. = _Z!1e tons. <br />F. ADSORPTION WIDTH e-1- A L4 �-o t4 <br />1. Percolation rate in top 12 inches of soil is mpi <br />2. Select allowable soil loadinfi rate from table on page E-, <br />4 N gpd/ ft2 <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br />1.20 gpd/ft2+ , �z,/ gpd/ ft2= ) � L. <br />Check this value on page E-16. <br />4. Multiply adsorption width ratio by rock layer width to get <br />requires: adsorption width; <br />Absorption Width Sizing Table <br />pervolsdollRr <br />is M-1-pv <br />Gnh IMP l) <br />Soil Teslure <br />Gallom <br />pu dey per <br />puan Lela <br />Raiool <br />AbwWien width <br />to Reek Layer <br />Width <br />Fa.1er 11M 0.1 <br />Coraa Sand <br />---- <br />--•- <br />0.1 IDS <br />Surd <br />1.20 <br />1.00 <br />0.110300 <br />run Sand •• <br />0.60 <br />2.00 <br />64015 <br />Sally laent <br />0.79 <br />1.52 <br />16 to 30 <br />I.eara <br />0.60 <br />2.W <br />31 D 45 <br />Sik I. hm <br />2.40 <br />461060 <br />Coy Leotn <br />12 <br />�lS <br />2.67 <br />60 to 120 <br />Clay <br />0.2♦ <br />5.0U <br />Slower than <br />Clay <br />--- <br />120' <br />F <br />
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