Laserfiche WebLink
1. If landslope Is 2.9 pciccnt or Ict^ basal width indudes both the <br />upslope and downslope dike widths, <br />Z Calculate minimum mound size based on geometery: <br />a. Determine depdi of dean sand fill at uiMlope edge of rock <br />layen Se/wation /.!_ feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slept Difference <br />^ X — %-t»100« — feet <br />c Add depth of dean sand depth of dean sand for <br />separation at upslope edge (2a) to depth of rock layer to <br />rock depth and the depth of cover to find the toul mound <br />height at upslope edge of rock layer; <br />y.7 ft^ lft»lft«3.3 feetSo»^04 <br />d. Enter table on page bottom with landslope and upslope <br />dike ratia Select dike multiplier of H_____. <br />e. Multiply dike multiplier by upslope mound height <br />to get upsiopedike vddth: ~3-3 x ^ = 1*^ feet <br />f. Add die depth of slope difference (2b) to the upslope <br />height to get die downslope height - <br />g. Enter table on page E-18 with landslope and downslope <br />dike ratio. Select dike multiplier of <br />h. Muldply dike multiplier by downslope mound height <br />to get downslope dike width:__- x feet <br />i. Mininmum mound width is the sum of upslope dike <br />width plus roc^ layer widm plus doumslope dj^^^ <br />j. Subtract the Minimum width G.i from the Absorption <br />width F.4 to find the Additional Downslope required for <br />Absorption <br />ft ft. -fwt <br />k. Add the Additional Downslope required for Absorption <br />to the downslope dike width and recalulate the Total "" - - • * <br />Mound Width which is is the sum of upslope dike <br />Vto^>V width plus rock layer width plus downslope dike width ^ ‘ <br />l:t ft4 ;o ft^ ]•! ft = feeti90^-ru I* <br />'Ha' 1. Total mound length is the sum of upslope dike width <br />plus rock layer length plus upslope dike width; <br />_r3 ft*^_LV ft + _/u_fl= HO feet <br />M at <br />dowMIaiw <br />4cl 7:1 kl 4:1 <br />-t^ <br />kl 7:1 M <br />0 la 40 10 10 7.0 10 4.0 10 40 7D 10 <br />I i»417 S34 414 7 51 2«1 }«1 474 144 454 741 <br />3 ji*4J«55.1 4*3 ■ 14 2*5 J-0 4:4 514 4 14 <br />t JA-:45;rt:»7 7;.• •:4"'5 m 5 7.^45 <br />4 ail 47*4Zi :.»i v:2 3m 3 45 417 4M 544 4U4 <br />S 351 SO)447 157 liJ77 341 131 4UU 442 11*$71 <br />4 3i4 124 7.14 «Jt 1307 214 321 IIS 44t 443 541 <br />7 IJO 114 744 1034 1171 241 112 170 421 470 SII•l.tS IM 131 1114 1541 2.43 3!0 157 405 4.4*4J5«4.11 42S *0*1304 1*42 314 2«4 145 140 410 445 <br />43«♦ C :co I5fl0 3131 311 3*4 111 ITS 413 444 <br />n 4U :i4 ::ii 1745 3i:4)3 34 2;*121 1.41 1«5 424 <br />u 444 74*1210 2U1 4171 221 270 113 <br />14*140 4i»