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1996-01-21 Septic System Design Report
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1996-01-21 Septic System Design Report
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5/22/2025 3:50:16 PM
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x Address Old
House Number
165
Street Name
Cristofori
Street Type
Circle
Address
165 Cristofori Circle
PIN
3111823430014
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MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated gpd <br />or measured - x 1.5 = gpd. <br />B. SEPTIC TANK LIQUID VOLUMES <br />i- w5 o 4 I- I o o G gallons <br />C. SOUS (refer to site evaluation) <br />I. Depth to restricting layer = � a inches <br />2. Depth of percolation tests = ) : " inches <br />3. Percolation rate ) 3 .L- mpi <br />4. Land slope y % <br />Erumated Sewage Flow in Gallas per Day ftpM <br />Number <br />of <br />Type I <br />Type It <br />Type III <br />Type IV <br />aeaoomr <br />2 <br />30D <br />225 <br />Io <br />60% <br />3 <br />ISO <br />300 <br />219 <br />01 <br />4i <br />4 <br />S <br />600 <br />750 <br />37S <br />ISO <br />I 236 <br />2" <br />•�• <br />6 <br />900 <br />IOSO <br />525 <br />600 <br />332 <br />370 <br />.�. <br />Ming" <br />8 <br />120D <br />675 <br />Ia <br />of <br />licdtooanr <br />� <br />2 or ku <br />750 <br />1.125 <br />3 or 4 <br />1. ow <br />13a1 <br />S a 6 <br />1 Soo <br />2.250 <br />7 or 9 <br />IODD <br />3.00D <br />over 9 <br />Sea G6. C-6 <br />(I 13) <br />D. ROCK LAYER D34ENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: A x 0.83 = <br />i, gpd x 0.83 sq. ft. / gpd = <br />2. Select width of rock layer (10 feet or less) = io ft. <br />3. Length of rock layer = area + width = Rock Bed <br />;oti' sq. ft. i /o ft. = Iv ft. <br />;?�� • th s10 fc <br />E. ROCK VOLUME <br />�-- Length <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />rid 4 sq. ft. x 1-o-L ft. _ ► V cu. ft. <br />2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />�,� cu. ft. y 27 = a n cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />-a q cu. yd. x 1.4 ton/cu. yd. = 34 tons. <br />F. ADSORPTION WIDTH L%-avc )-vaw <br />1. Percolation rate in top 12 inches of soil is 13, L mpi <br />2. Select allowable soil loading rate from table; <br />a gpd/ft' <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br />1.20 gpd/ft2= , u Sgpd/fry = L r Q <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />o.c,� x I0 ft =3)..17 ft <br />W6d1b <br />7a►1a <br />PercalabonRaw <br />�luure. pn esh <br />Soil Texture�� <br />e'& <br />(mp,1 <br />Faster than 0.1 <br />Coarse Sand <br />110 <br />1.00 <br />0.1 10 5 <br />Sand <br />110 <br />1.00 <br />0.1 to 5 <br />Fine Sand- <br />0.60 <br />2.00 <br />6 to 15 <br />Sandy Loam <br />0.79 <br />132 <br />16 to 30 <br />Loam <br />0.60 <br />2.00 <br />31 to 45 <br />Silt loam <br />0.50 <br />2.40 <br />46 to 60 <br />Clay Loam <br />0.45 <br />2.67 <br />61 t0120 <br />Clay <br />024 <br />3.00 <br />Slower than 120 <br />Clav <br />-- <br />- <br />- SW 1a" 50R A mom of rrnr R tf V Rh ban& <br />
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