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1991-11-11 Septic System Design Report
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1991-11-11 Septic System Design Report
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Last modified
5/7/2025 11:55:47 AM
Creation date
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x Address Old
House Number
4745
Street Name
Creekwood
Street Type
Trail
Address
4745 Creekwood Trail
PIN
3011823330008
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IVIL/UIVU ULLOMIlIV lVUltA01VILLL <br />(For I -lows up to 1200 gpd) <br />A. FLOW <br />Estimated --�� gl)cl (seepages D-7 or l-3, 4, 5) <br />or measured gpd x 1.5 = <br />B. SEPTIC TANK LIQUID VOLUMES <br />foo0 _# / - tewpA gallons (see pages C-3 or C-5) <br />C. SOILS (refer to site evaluation) <br />1. Depth to restricting layer = inches <br />2. Depth of percolation tests = I':t inches <br />3. Percolation rate '� mpi <br />4. Land slope Q % <br />1'.nimaled Sewage Fluws in Odlu�,s pv day <br />tcl+d> <br />of <br />Type I <br />Type 11 <br />Typn ill <br />T�pe <br />Iledrooms <br />2 <br />3011 <br />225 <br />180 <br />9 <br />450 <br />3W <br />219 <br />Boa <br />4 <br />6011 <br />375 <br />256 <br />5 <br />750 <br />450 <br />294 <br />1. <br />6 <br />9011 <br />525 <br />332 <br />1 <br />7 <br />1050 <br />600 <br />370 <br />Ill <br />8 <br />1200 <br />675 <br />AIN <br />ed w.w <br />Seek Ta.k Cap ilkra, in p/r. <br />Nwnhe e! <br />Miain vin Llpid <br />lAvid espacily .ith <br />Ikdr.s..a <br />C-PW" <br />karkqr di4 wal <br />2wkn <br />750 <br />1IM <br />3w4 <br />Ian <br />ISM <br />4wi <br />IS1U <br />tLS11 <br />7.9.9 <br />iJal <br />JIM <br />arm • <br />...... <br />D. ROCK LAY':l% DIMENSIONS <br />1. Multiply ilcw rate by 0.83 to obtain required area of rock <br />layer: Daily Flow x 0.83 - <br />,07-15*6 gpd x 0.83 sq. ft./gpd = =sq. ft. <br />2. Select width of rock lay 1r (10 feet or less) _ . AO - ft. <br />3. Length of rock layer = Area + Width - <br />4az Sq. ft. + ,! ft. = &9 ft. Rock Bed <br />E. ROCK VOLUME <br />1. . ,w *Multiply rock area by rock depth to get cubic feet of rock; <br />} �esq. ft. x � f c. _ �,�,Zcu. ft..' <br />` Divide cu. ft. by 27 cu. ft. /cu. yd.. to get cubic yards; <br />ft. + 27 = cu. yd. <br />3..:`. `Multipl cubic yards by 1.4 to get weight of rock in tons; <br />'cu. yd. x 1.4 ton/cu. yd. -.U. tons. <br />F. ADSORPTION WIDTH <br />1. Percolation rate in top 12 inches of soil is �� mpi <br />2. Select allowable soil loadic� rate from table on page E-; <br />,P glad/ft' <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.2U gpd/ft' by allowable soil loading rate; <br />1.20gpd/ft2+ -5-o gpd/ft2= a-V6 . <br />Check this value on page E-16. <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />.IV. YoxL_ft=eft <br />��`�.•..,......••..•. �Ividth slily <br />� Lengih <br />Absllrpllun WWII Sir•InR"able <br />I'acalnlonv.+ <br />I" Mhwut pv <br />lick IMPI` <br />Soil Tealwe <br />Galion <br />pn d.y per <br />rryare lwr <br />Wool <br />Alaarp,km . hhl <br />InNock Layer <br />Wkhh <br />FlKicr 11,an 0.1 • <br />Corse Sand <br />• •... <br />..... <br />0.1163 <br />Saw 1 <br />1.20 <br />1.00 <br />0.1 M 5 60 <br />Fine Sand 0. <br />0 602.110 <br />610IS <br />Sandy Lisa <br />0.79 <br />1.32 <br />1610.10 <br />Loam <br />0.60 <br />2.110 <br />31 10 45 <br />SIN Lora <br />0.50 <br />2.40 <br />4610 60 <br />Clay Lawn <br />0 4S <br />2.67 <br />60 10 120 <br />Clsy <br />0.24 <br />S.00 <br />Sloweslhm <br />Clay, <br />_ <br />_... <br />JIV.. <br />
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