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A. Determine pump capacity: <br />Gravity Distribution <br />1. Minimum suggested is 600 gallons per hour (10 gpm/ to stay ahead of <br />water use rate. <br />2. Maximum suggested for delivery to a drop box of a home system; is 2,700 <br />gallons per hour (45 gpm) to prevent build-up of pressure in drop box. <br />Pressure Distribution <br />3. a. Select number of perforated laterals 3 <br />b. Select perforation spacing - 31'- ft. <br />c• Subtra t 2 ft. from the rock layer length. <br />e �r,�1e - 2 ft. _ _-3 ft. <br />d. Determine the number of spaces betwecii perforations. <br />Length perf. spacing = 1--?. ft. +,,-S_ ft. -_ spaces <br />C. ;t 4 spaces+ 1 -3S perforations/lateral <br />f. Multiply perforations per lateral by number of latcrils to <br />gZ <br />total nuc. ' -cr of perforations. <br />.' x t SI;. = Z,� Fcrforatlons. <br />g x„� =gpm• �I3�. IPFY <br />SELECTED PUMP CAPACITY�� gpm <br />B. Determine head requiremenin: <br />1. Elevation difference �ctwcen pump anti ,point of lii c`la: <br />I �V feet <br />2. If pumping to a pressure distribution system, add tive fcc:.;,r pressure <br />required at manifold <br />feet <br />3. Friction loss <br />a. Enter friction loss table with gpm and pipe d,aa-.e:rr. <br />Read friction loss in feet per 100 feet from tabic:. <br />F.L.- V,52 ft./100 ft of pipe <br />b. Determine total pipe length from pump to d:5ch,:. ye <br />point. Add 25 percent to pipe length for tittle,,; <br />loss, or use a fitting loss chart. Eltuivalcnt pipe <br />length -1.25 times pipe length <br />_j -5'Z>- x 1.25 = 1_S1_eW- feet <br />c. Calculate total friction loss .y multiplying <br />friction loss in ft/ 100 ft by equivalcli: pipe len;th. <br />Total friction loss = I e: e; x _;) - '_+100 = S feet <br />4. Total head required is the sum of elevation difference, <br />special head requirements, and total frictiion loss. <br />C +<- <br />(1) (2) (R) <br />TOTAL HEAD a `6 feet <br />Pump selection <br />1. A pump must be selected to deliver at leas: -.l._ sp," (S,e? A <br />with at least _a_jj_ feet of total head (Step B). <br />END PEprORATION OF A PcnronATED LATERAL <br />nr. Rine, Seel P•..• 1. tw.hN <br />tlelere Vbcrq :Ana LarN <br />ABLE Or PER a:Oh DISC HAZGr5IN CI1161 <br />!cad 'cr•.orallondlmneterin:incal <br />"_G•u cow <br />G.2t1 i <br />It.0a <br />036 <br />0.74 <br />O.:.Y I <br />1 •r <br />LAIN of C-10/1.16 reG•( I- rY' <br />• Lent.. Sone Lee•I <br />•.w •t a•r r ww a••r•n <br />I 23 j <br />- IeVr1 ,eePwl <br />r•a•.• e1«,r•ww,ir <br />' •.711' - <br />�MM Cea WN be <br />i {13 I <br />La <br />.11,f •, <br />-AI levo I: q Cu ;. <br />� <br />�i'n, n.n� .iA Pn[.�• <br />•� •1 !lock LII. <br />V_e.,r,ru.m Lr.l,ed e1 <br />CIIGe Sora Neer <br />!•'i•e. 0 LIrUW <br />nr. Rine, Seel P•..• 1. tw.hN <br />tlelere Vbcrq :Ana LarN <br />ABLE Or PER a:Oh DISC HAZGr5IN CI1161 <br />!cad 'cr•.orallondlmneterin:incal <br />�:-C ..r . <br />.4 <br />P•rr.t of k71sc::ar_c <br />9�9 - <br />I 1 L•:cv�ti�n Ji;: •r.rcc <br />19W. <br />F -ib -) <br />1.5 inch .0 inc 3.11 ir.ch <br />., rt,:,,M im rt or a.;c <br />0.61) j <br />G.2t1 i <br />It.0a <br />036 <br />0.74 <br />O.:.Y I <br />1 •r <br />1 • 2S I <br />O.. Y <br />I <br />I 23 j <br />0:19 <br />1.17 <br />3.0 <br />15 <br />i {13 I <br />La <br />1.73 <br />0 <br />1.:6 <br />AL.'se 1.0 foot of 1hc.ld fee residential tV1.1c; . <br />� 1,.':c <br />..•r• �r 1.r�d !nr <br />tPcr r I <br />_.:7 <br />I 5.23 ! <br />.._.J <br />�:-C ..r . <br />.4 <br />P•rr.t of k71sc::ar_c <br />9�9 - <br />I 1 L•:cv�ti�n Ji;: •r.rcc <br />19W. <br />F -ib -) <br />1.5 inch .0 inc 3.11 ir.ch <br />., rt,:,,M im rt or a.;c <br />0.61) j <br />G.2t1 i <br />I 13 <br />I 11.96 I <br />O.:.Y I <br />1 •r <br />1 • 2S I <br />O.. Y <br />I <br />i <br />15 <br />i {13 I <br />G..`LI <br />3. is <br />..11 <br />0.16 <br />t 30 <br />I 5.23 ! <br />i._3 <br />0.23 <br />15 <br />j 7.90 <br />I ?.a% <br />I 40 <br />;1.,t" <br />1 45 <br />'70 <br />5j <br />76 <br />60 <br />I <br />', <br />5.',0 <br />� <br />I r�.s: <br />