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1990-05-05 Septic System Design Report
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1990-05-05 Septic System Design Report
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4/23/2025 4:19:44 PM
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G. <br />1. <br />2.' <br />DOWNSLOPE DIIM WITH <br />If landslope is 3% or man. l.ibtract rock layer width from <br />adsorption width to ob oM minimum downslope dike toe <br />_0 h - e ft= /0 feet <br />Calculate Minimum mound size based on geometery: <br />a.. Determine depth of dean sand fill at upslope edge of rock <br />layer. Separation 1, S feet <br />b. Multiply rock layer width by landslope <br />to determine drop in elevation; <br />Slope Diffm m sorsrottoo <br />Al x _.L_% - 100 = O. S feet ULs1oM Width <br />c. Add depth of dean sand for separation (7a) tset <br />at upslope edge, depth of rock layer (1 fwt) to depth of <br />cover (1 foot) to find the mound height at the upslope edge <br />of rock layer, <br />/. S ft + ift + lft = .2,j- feet <br />d. Enter table with Wulslope and upslope dike ratio: <br />Select dike multiplier of 3.33 <br />e. Multiply dike multiplier by upslope mound height <br />to find upslope dike width:, 3L x _Z. L = A 7 feet <br />f. Add depth of clean sand for slope difference (2b) at <br />downslope edge, to the mound height at the upslope edge <br />of rock layer (2c) to find the downslope height; <br />.&S ft + o. _ ft = . D feet <br />g. Enter table with landslope and downslope dike ratio. <br />Select dike multiplier of ' S. Do <br />i.. Multiply dike multiplier by downslope mound height <br />to get downslope dike width�o -Y X-0 = Z 0 feet <br />L Compare the valued of step G.1 and step G.2h Select the <br />greater of the two values as the downslope dike width; <br />2 O feet <br />j. `i'otal mound width is the sum of <br />upslope dike (G.2e) width plus rock <br />layer width (D.2) plus <br />downslope dike width(G.21); <br />LL.7 ft+eft+20_ft= _%Z feet <br />k. Total nzo4nd length is the sum of <br />upslope dike width (G.2e) plus rock layer <br />length, (D.3) plus upslope dike width (G.2e); <br />to eft+ SD ft+l&Zft= 73. Vfeet <br />bm,ro-0 + —9w- +J0 .7. ) 1$4- <br />1 took Ct+Ver <br />I rest a OR <br />lost <br />Slope Otlferoeeo _ <br />Rock Bod Width <br />fool Oowas1000 width <br />foot <br />Tent Nast% <br />Al <br />49 <br />fd <br />61 <br />r.1 <br />7n <br />al <br />VPW <br />11 <br />61 <br />rt <br />Li <br />, <br />sw <br />o, <br />LI <br />Y <br />1111 <br />114 <br />T# <br />&4 <br />411 <br />to <br />w <br />T1 <br />u <br />1 <br />W <br />4V <br />taisf <br />W <br />63 <br />to <br />los <br />LT1 <br />7A1 <br />W <br />1VA <br />41% <br />aa• <br />Los <br />Lib <br />GU <br />614 <br />TAS <br />4.M <br />: <br />1?� <br />W435 <br />'MW <br />Aid <br />TAR <br />W <br />5 i <br />7]s <br />2As <br />1• <br />iN <br />4A <br />In <br />a <br />aM <br />&N <br />L46 <br />W <br />W <br />• <br />f <br />L o <br />ZD <br />alt <br />as <br />as <br />6d1 <br />W <br />idl <br />lY <br />W <br />LD <br />ase <br />W <br />a47 <br />W <br />LN <br />4.10, <br />L71 <br />w <br />• <br />LIs <br />W <br />ti <br />to <br />T.M <br />T1 <br />*a <br />IW <br />saw <br />U22 <br />W <br />is <br />&U <br />Lfo <br />as <br />ale <br />LU <br />44s <br />T <br />LO <br />LU <br />UA <br />Un <br />sssa <br />711 <br />Lis <br />W <br />in <br />ip <br />LO <br />dol <br />110 <br />aM <br />4N <br />•Ai <br />• <br />10 <br />au <br />4al <br />as <br />sAs <br />ttYUs <br />qOs <br />f1» <br />7i1 <br />Las <br />an <br />Lit <br />L.>s <br />in <br />LAI <br />an <br />116 <br />•u <br />431 <br />Tu <br />l3Ji <br />2W <br />7041 <br />an <br />LU <br />171 <br />ale <br />los <br />to <br />ids <br />•AL <br />12 <br />40 <br />TAO <br />no <br />
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