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X <br />ope is 3% or more, subtract rock layer width from <br />on width to obtain minimum downslope dike toe for <br />absorption: <br />L,7 ft - _LC) ft = feet <br />2. Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation /.:5' feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slopc Difference <br />,/0 x ' %+100= •3 feet <br />c. Add depth of clean sand depth of clean sand for <br />separation at upslope edge (2a) to depth of rock layer to <br />rock depth and the depth of cover to find the total mound <br />height at upslope edge of rock layer; <br />/. :3 ft + 1 ft + 1 ft = 3.'3 feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of 3 .-<q <br />e. Multiply dike multiplier by upslope mound height <br />to get upslope dike width: 3_ x 3.5'? = 1-a feet <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height <br />3, z + = 3, C, _feet <br />g. Enter table on page bottom with landslope and <br />downslope dike ratio. t <br />Select dike multiplier of 4. Sy <br />h. Multiply dike multiplier by downslope mound height <br />to get downslope dike width: 3• c, x q.sv = I G feet <br />i. Compare the values of step G.1 and Step G.2.h. Select the <br />greater of the two values as the downslope dike width; <br />�'I feet ..........•• <br />j. Total mound width is the sum of upslope dike Kocktk-d WWhk%_4a'' .'h SWI 01—JZ <br />width plus rock laver Nvidth plus d ownsln^_ <br />dike width; I,�Kock <br />+ /_ ft + ft = feet �,,I,.aki►►a_ 1X. <br />k. Total mound length is the sum of upslope ; <br />dike width plus rock later length plus <br />upslope dike width; <br />lam- ft+ U- 'e, ft, )7 —ft= _ r -_ fact t,..�. •��. _/ <br />3:1 <br />ll <br />wnslopc <br />5:1 <br />LI <br />7:1 <br />3.1 <br />4.1 <br />UPSIOPC <br />5:1 <br />4:1 <br />7:1 <br />it <br />16 43npt <br />0 <br />3A <br />40 <br />SO <br />4.0 <br />7.0 <br />30 <br />40 <br />S.0 <br />40 <br />7.0 <br />t0 <br />1 <br />301 <br />417 <br />434 <br />7M <br />711 <br />1.3 <br />474 <br />544 <br />454 <br />7AI <br />3 <br />3.11 <br />3� <br />e <br />536 <br />S. <br />417 <br />7.12_. <br />1.14 <br />7 0 <br />7 <br />?.7. <br />4.54 <br />4.35 <br />534 <br />SM <br />414 <br />S <br />4.f3 <br />4 45 <br />l <br />330 <br />34 <br />4.St <br />!:4 <br />S: _ <br />67° <br />7!1 <br />i.K. <br />41' <br />4L1 <br />5 <br />406 <br />5.0. <br />4:" <br />t5. <br />'•: <br />4ni <br />c._ <br />S1: <br />S71 <br />4 <br />3K <br />SM <br />714 <br />934 <br />1:07 <br />75t <br />?J <br />3 i <br />44; <br />493 <br />341 <br />7 <br />3B3 <br />SSi <br />7.N <br />1034 <br />1373 <br />7Y <br />).11 <br />370 <br />4 2 <br />470 <br />S33 <br />1 <br />3.1s <br />INi3J <br />1154 <br />1511 <br />143 <br />301 <br />351 <br />4 U <br />441 <br />4M <br />1 <br />4l1 <br />43S <br />t.tv <br />1]04 <br />1117 <br />334 <br />7.9. <br />345 <br />310 <br />430 <br />ILS <br />10 <br />4]9 <br />40 <br />100 <br />1s0o <br />3333 <br />711 <br />70 <br />733 <br />375 <br />4.t7 <br />411 <br />11 <br />4.0 <br />7.14 <br />11.11 <br />t745 <br />3043 <br />714 <br />774 <br />323 <br />341 <br />3.9s <br />434 <br />11 <br /><N <br />:.N <br />13-0 <br />7:43 <br />4375 <br />771 <br />7.:0 <br />317 <br />3to <br />390 <br />401 <br />