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V. 1_i0A`!I <br />�. If landslope is 2.9 percent or less, basal %vidth includes both the <br />upslope and downslope dike widths, <br />2. <br />Calculate minimum mound size based on geometery: <br />a. Detern-ine depth of clean sand fill at upslope edge of rock <br />layer: Separation A . o , feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slope Difference <br />l x'_%+100=. -s feet <br />c. Add depth of clean sand depth of clean sand for llq. W <br />separation at upslope edge (2a) to depth of rock layer to <br />rock depth and the depth of cover to find the total mound <br />height at upslope edge of rock layer; <br />;.o ft + 1 ft + 1 ft = 1-4.o feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of ? .s <br />e. Multiply dike multiplier by upslope mound height <br />to get upslope dike width: 3. s -i x i. _ _i �j feet <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height . c: + -Z ='� feet <br />g. Enter table on page E-18 with landslope and downslope <br />dike ru:io. Select dike multiplier of L; .S -i <br />h. Multiply dike multiplier by downslope mound height <br />to get downslope dike width: 4. '� x 4.SLl _ _-Li o feet <br />i. Mininmum mound width is the sum of upslope dike <br />width plus rock layer width plus downslope dike width; <br />Iy_ft+eft+ -�v ft= _y feet <br />j. Subtract the Minimum width G.i from the Absorption <br />width FA to find the Additional Downslope required for <br />Absorption <br />ft- 4J ft = -t,) feet `PSIC <br />k. Add the Additional Downslope required for Absorptio <br />to the downslope dike width and recalulate the Total <br />Mound Width which is is the sum of upslope dike <br />width plus rock layer width plus downslope dike vvidt;, <br />-Le ft+j L) ft+ -�-L) ft = L, 4_feet <br />1. Total mound length is the sum of upslope dike width <br />plus rock layer length plus upslope dike width; <br />ft +. (,-Ie ft + �U ft - ��_ feet <br />a o -+ ('Ct/ -*- a u o <br />1 bacww <br />0..,1oA <br />rw s.p. 1311h,ew <br />NatNat 16d wwN <br />Uu..wla�. lvau <br />�----Total Length 9 L <br />3:1 <br />4:1 <br />wns upc <br />5:1 <br />61 <br />7.1 <br />3.1 <br />4.1 <br />U04OPC <br />5:1 <br />kl <br />7:1 <br />e.l <br />v <br />S .tope - ., <br />0 <br />3.04.0 <br />5.G <br />70 <br />30 <br />40 <br />5.0 <br />6.0 <br />7.r, <br />8.0 <br />1 <br />300 <br />1.17 <br />5..'6 <br />6 N <br />' 41 <br />: ul <br />3 tl5 <br />4 76 <br />566 <br />6 V <br />7.11 <br />3 19 <br />3.?5 <br />5 IA <br />. e2 <br />,. <br />�:;; <br />4 i, <br />'i 31i <br />6 14 <br />6 W <br />230 <br />la � <br />,� <br />'. <br />'� <br /><3 <br />��• <br />., <br />4 <br />" 1:4 <br />7 e <br />.S <br />6.64 <br />7 <br />• ". <br />: ro <br />3.45 <br />4.17 <br />G 64 <br />546 <br />6.06 <br />5 <br />353 <br />500 <br />6.67 <br />6.57 <br />i 77 <br />I 2 61 <br />313 <br />4. W <br />4.62 <br />5.19 <br />5.71 <br />6 <br />3.66 <br />5.26 <br />7.14 <br />9.33 <br />1207 <br />2-4 <br />3.23 <br />3 15 <br />4.41 <br />4 93 <br />5.41 <br />7 <br />380 <br />556 <br />7.69 <br />1034 <br />1173 <br />2 4A <br />3.12 <br />3 %, <br />4 23 <br />1.70 <br />5.13 <br />e <br />3.95 <br />5 tl9 <br />9.33 <br />11 S4 <br />1 i 91 <br />2 32 <br />3.23 <br />3.5: <br />425 <br />4.49 <br />LY <br />9 <br />4.11 <br />625 <br />9 09 <br />131K <br />1 y.v2 <br />236 <br />2 94 <br />3.45 <br />3.90 <br />4.30 <br />465 <br />10 <br />429 <br />667 <br />;('D <br />I..,.fY <br />_333 <br />231 <br />246 <br />333 <br />375 <br />412 <br />444 <br />I; <br />4.49 <br />7.14 <br />11.11 <br />1-L5 <br />J:3 <br />2:6 <br />2 7 <br />3.23 <br />361 <br />395 <br />4.26 <br />12 <br />469 <br />7.69 <br />12.5 <br />:1.43 <br />43.75 <br />221 <br />2.70 <br />3.12 <br />3.49 <br />3 bO <br />449 <br />