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G. D(.,'.'%...,-1. 1. L:IKL 1'►'iLT11 <br />1. If landslope is 2.9 percent or less, basal width includes both the <br />upslope and downslope dike widths, <br />2. <br />Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation z , o feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slope Difference <br />/ x _Z%+100=, -L- feet <br />c. Add depth of clean sand depth of clean sand for <br />separation at upslope edge (2a) to depth of rock layer to <br />rock depth and the depth of cover to find the total mound <br />height at upslope edge of rock layer; <br />x.o ft + 1 ft + 1 ft = 1-i.0 feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of 3 .'7 <br />e. Multiply dike multiplier by upslope mound height <br />to get upslope dike width: 4.L) x 3.9 = i_ feet <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height H . _, + . i = Li . z feet <br />g. Enter table on page E-18 with landslope and downslope <br />dike ratio. Select dike multiplier of !4 •3 5r <br />h. Multiply dike multiplier by downslope mound height <br />to get downslope dike width: 4. t x Lt -s 5r = i / feet <br />i. Mininmum mound width is the sum of upslope dike <br />width plus rock layer width plus downslope dike width; <br />_L�' f.'+ )0 41 feet <br />j. Subtract the Minimum width G.i from the Absorption <br />width F.4 to find the Additional Downslope required for <br />Absorption <br />an ft - Lr� ft = -i L feet "'" <br />k. Add the Additional Downslope required for Absorptio. <br />to the downslope dike width and recalulate the Total <br />Mound Width which. is is the sum of upslope dike <br />width plus rock layer width plus '-,wnslope dike width <br />ft+lift+/ cd it = lam- -,feet <br />1. Total mound length is the sum of upslope dike width <br />plus rock layer leng-h plus upslope dike width; <br />ft +. ft + ft = 'Pid feet <br />/04 <br />I be CAM <br />14..t.d <br />L2 im S.p..."- <br />9" 4N Wd16 <br />Ib.rr61�. YM4O <br />TOW Length -� V <br />/oy <br />kt <br />l'1 <br />Wns opepS <br />5:1 <br />al <br />7:1 <br />3:1 <br />4:1 <br />o}%: <br />S.1 <br />&1 <br />7:1 <br />9:1 <br />s MOPP <br />0 <br />3A <br />l0 <br />S.0 <br />a0 <br />7.0 <br />3.0 <br />4.0 <br />SO <br />60 <br />7.0 <br />6A <br />1 <br />lop <br />4.17 <br />SM <br />6311 <br />7;1 <br />291 <br />475 <br />516 <br />64 <br />7.41 <br />3.19 _ _ <br />COSH <br />10- <br />V'.LLi,-� <br />� <br />i 36 <br />6 14 <br />600 <br />.Y1 <br />{sl <br />3M <br />71_ <br />7,.- <br />3.57 <br />i r. <br />3\ <br />615 <br />4 <br />3.41 <br />416 <br />n ;_i <br />7.6. <br />2 #a <br />3.45 <br />41-1 <br />i 64 <br />5.46 <br />606 <br />S <br />3S3 <br />5.00 <br />a67 <br />6.57 <br />IUir <br />261 <br />3.33 <br />4fo <br />462 <br />5.19 <br />5.71 <br />6 <br />366 <br />5.26 <br />7.14 <br />036 <br />12.07 <br />2.S4 <br />3.23 <br />]6S <br />441 <br />4-93 <br />SAI <br />3110 <br />S 36 <br />7.69 <br />10.34 <br />13.73 <br />246 <br />312 <br />370 <br />4.2) <br />4.70 <br />S.13 <br />1 <br />3.9s <br />S.61 <br />6.33 <br />ItS4 <br />15.91 <br />242 <br />1.10 <br />357 <br />416 <br />449 <br />4M <br />9 <br />4.11 <br />625 <br />9.09 <br />13 fM <br />16 92 <br />236 <br />2.04 <br />3.45 <br />390 <br />4.30 <br />465 <br />10 <br />429 <br />667 <br />I OA <br />15110 <br />2131 <br />231 <br />2 66 <br />3.11 <br />37-1 <br />4 12 <br />444 <br />11 <br />4" <br />7.14 <br />11.11 <br />171; <br />3n 41 <br />226 <br />2.76 <br />1 -1 <br />3.61 <br />3.9S <br />416 <br />12 <br />4b9 <br />TO <br />1230 <br />2143 <br />4175 <br />2.21 <br />270 <br />3.12 <br />3A9 <br />VW <br />4.0 <br />