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v. -I ..... . ._ .. . . . <br />1. If landslope is 2.9 percent or less, basal width includes both the <br />upslope and downslope dike widths, <br />2. <br />Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation 1. Z feet <br />b. Multiply rock layer,.ti,idth by landslope to determine drop <br />in elevation; Slope Difference -1 <br />)c x - 100 = -- feet <br />c. Add depth of clean sand depth of clean sand for l �� <br />separation at upslope edge (2a) to depth of rock layer to <br />rock depth and the depth of cover to find the total mound <br />height at upslope edge of rock layer; <br />1.'Z ft + 1 ft + 1 ft = 3 .-2- feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of Y <br />e. Multiply dike multiplier by upslope mound height <br />to get upslope dike width: 2,7- x 4 =1_ feet L1Sr- <br />f. Add the depth of slope difference (2b) to the upslope <br />19 + <br />height to get the downslope height -* -= -feet <br />g. Enter table on page E-18 with landslope and downslope <br />dike ratio. Select dike multiplier of <br />I•. Multiply dike multiplier by downslope mound height <br />to get downslope dike width: x ----= feet <br />i. Mininmum mound width is the sum of upslope dike <br />width plus rock layer width plus downslope dike wiAt.h; <br />feet <br />j. Subtract the Minimum width G.i from the Absorption <br />.%-idth FA to find the Additional Downslope required for <br />Absorption <br />ft--- -tt - feet `'Pe <br />k. Add the .'additional Downslope required for Absorptio <br />to the downslope dike width and recalulate the Total <br />Mound Width which is is the sum of upslope dike <br />«•idth plus rock layer width plus downslope dike .%-idtli <br />-L.<�_ft+)J f t + ISS ft =feet <br />1. Total mound length is the sum of upslope dike width <br />plus rock layer length plus upslope dike width; <br />ft + _L�t_ ft + ft = � feet <br />�------Tool LeNth <br />3:1 <br />1:1 <br />wns opeps <br />5:1 <br />6:1 <br />7:1 <br />3.1 <br />f <br />{ 1 <br />°Fx <br />S1 <br />6.1 <br />7:1 <br />to <br />% .wP. <br />0 <br />3.13 <br />IA <br />5.0 <br />60 <br />7.0 <br />3.0 <br />40 <br />50 <br />60 <br />7.0 <br />IA <br />1 <br />3 09 <br />417 <br />S.26 <br />6 ]6 <br />753 <br />291 <br />3 4; <br />4 76 <br />S 66 <br />6 4 <br />7.41 <br />3'.G <br />{.35 <br />59•, <br />be? <br />!11 <br />:n7 <br />770{:1 <br />5.36 <br />614 <br />690 <br />341 <br />t 76 <br />s :3 <br />7.!io <br />w.72 <br />2.M <br />3 {i <br />/ 17 <br />{ 64 <br />546 <br />6" <br />5 <br />3S3 <br />50U <br />t <br />657 <br />IU77 <br />261 <br />333 <br />{.W <br />{62 <br />S.16 <br />S.71 <br />6 <br />3.66 <br />S26 <br />7.1{ <br />9.36 <br />1207 <br />2S4 <br />323 <br />3.95 <br />111 <br />693 <br />S/l <br />7 <br />3M <br />556 <br />740 <br />103{ <br />1373 <br />2W <br />3.12 <br />370 <br />{.23 <br />1.70 <br />5.13 <br />6 <br />3.55 <br />S.Y <br />L33 <br />t1-4 <br />1591 <br />2Q <br />303 <br />3.S7 <br />6.05 <br />LH <br />{M <br />9 <br />1 11 <br />625 <br />9 0. <br />13 N <br />11.92 <br />276 <br />299 <br />345 <br />3.90 <br />4 30 <br />{ 15 <br />10 <br />{29 <br />667 <br />100 <br />is <br />2333 <br />2ll <br />2M <br />333 <br />3.75 <br />112 <br />{M <br />:1 <br />L46 <br />7.14 <br />1111 <br />17.5 <br />3C{3 <br />226 <br />276 <br />32.7 <br />3i1 <br />395 <br />{26 <br />12 <br />{b+ <br />7.69 <br />1750 <br />2i{3 <br />43.75 <br />221 <br />27U <br />3,12 <br />30 <br />'.10 <br />1.01 <br />