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MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated ") -(0 gpd (see pages D-7 or I-3, 4, 5) <br />or measured ^ gpd x 1.5 = <br />B. SEPTIC TANK LIQUID VOLUMES <br />)-pS(i -* )-logo gallons (seepages C-3 or C-5) <br />C. SOILS (refer to site evaluation) <br />1. Depth to restricting layer = 1 �t�� �,' inches �4t,�J 3%4a <br />2. Depth of percolation tests = I inches <br />3. Percolation rate ( - mpi <br />4. Land slope y % <br />Estimated Sewage Flows in Galluns per day <br />(ape) <br />Number <br />Ratio of <br />Ahaorpion width <br />to Rock Layer <br />Width <br />Fatter than 0.1 <br />Corse Sand <br />•- <br />of <br />Type I <br />ryp< 11 <br />Type ill <br />Type <br />Redroom s <br />Fun: Sand •• <br />0.60 <br />2.00 <br />IV <br />2 <br />300 <br />225 Igo <br />1610 30 <br />3 <br />450 <br />300 219 <br />boa <br />4 <br />600 <br />375 255 <br />1'a' <br />5 <br />750 <br />4'0 i 294 <br />60 to 120 <br />6 <br />900 <br />5:5 332 <br />TRW L <br />7 <br />1050 <br />6W 370 <br />laat <br />8 <br />1200 <br />675 I 409 <br />"resat <br />S"rtic T..k C.Pacit" 1. <br />.Namur of <br />MinvnMaiJaa L.qud <br />Ltqud-Fp aywmh <br />Bad -t. <br />r <br />� P-,ry <br />aarb.aa dopowd <br />2 m Mesa <br />750 <br />1125 <br />3K4 <br />I000 <br />ISOD <br />4 W 6 <br />15W <br />2250 <br />7.8 ar 9 <br />2000 <br />MW <br />wr9 <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: Daily Flow x 0.83 = <br />')gpd x 0.83 sq. ft./gpd = a �. sq. f0 16 -Pa= l.vy C2. Select width of rock layer (10 feet or less) _ / V ft. <br />3. Length of rock layer = Area + Width = <br />65,qL4 sq. ft. + JO- ft.= &4/ ft. <br />E. ROCK VOLUME <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />46�y sq. ft. x /.v� ft. = Z cu. ft. <br />2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />cu. ft. + 27 = 1'1 cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />cu. yd. x 1.4 ton/cu. yd. =Z, IV tons. <br />F. ADSORPTION WIDTH <br />1. Percolation rate in top 12 inches of soil is . 3 mpi <br />2. Select allowable soil loadin� rate from table on page E-; <br />L4 ,, gpd / f t2 <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft, by allowable soil loading rate;. <br />1.20 gpd, /ft2+ �gpd /ft2= a • 1,1? . <br />Check this value on page E-16. <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; - <br />�.'I j x 10 ft =� I"q ft <br />• . : ,a <br />ll <br />ti•ti•ti•ti•ti•ti•�•�•ti•ti•ti•\•ti•1•�• <br />!•!•!•!•!•!•!•!•!•t•!•!•!•I•t <br />ti•,.•�•�•,.•ti•ti•ti•ti•♦ ♦•+•�•v�• tdth 510 ft <br />f---- Lena, , <br />Absorption Width Sizing Table <br />Percolation Rate <br />in Minwespa <br />inch (MPI) <br />Soil Tcuure <br />Galbna <br />per day per <br />square font <br />Ratio of <br />Ahaorpion width <br />to Rock Layer <br />Width <br />Fatter than 0.1 <br />Corse Sand <br />•- <br />- <br />0.1605 <br />Sand <br />1.20 <br />1.00 <br />0.1 to 5 •• <br />Fun: Sand •• <br />0.60 <br />2.00 <br />6 to 15 <br />Sardy Lew <br />0.79 <br />1.52 <br />1610 30 <br />I am <br />0.60 <br />2M <br />31 lo45 <br />Silt Law <br />0.50 <br />L40 <br />46 to 60 <br />Clay Lard <br />0.45 <br />2.67 <br />60 to 120 <br />Clay <br />0.24 <br />5.00 <br />Slower than <br />Clay <br />-- <br />- <br />I20 <br />