Laserfiche WebLink
MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLUV <br />Filim.ud SeNp M& m c.ttM rQ Day (Spo <br />Nunbv <br />c <br />�� w. <br />�.... <br />, r' <br />Estimated „ gpd <br />or measured x 1.3 = gpd. <br />t]&* <br />gyp` <br />7 tr <br />Trs� III <br />n' <br />B. SEPTIC TANK LIQUID VOLUMES <br />2 <br />4 <br />300 <br />6 o <br />275 <br />375 <br />]so <br />256 <br />.o. <br />;- 1 r r gallons <br />6 <br />9011 <br />525 <br />332 <br />.�_. <br />w <br />Loam <br />7 <br />1410 <br />600 <br />370 <br />•~ <br />�� <br />2.40 <br />46 to 60 <br />120D <br />673 <br />�0{ <br />61 t0120 <br />C. SOILS (refer to site evaluation) <br />024 <br />3A0 <br />Slower than 120 <br />CL <br />1. Depth to restricting layer = inches <br />rr+. <br />t <br />w <br />.� <br />w"' <br />2. Depth of percolation tests = inches <br />� <br />`100 <br />2344 <br />750 <br />1.125 <br />3. Percolation rate ''• mpi <br />4. Land slope �l0 <br />1� <br />]� <br />7 w g <br />2.= <br />law <br />OWN <br />S"aLCi <br />(c 1.5) <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: A x 0.83 = <br />_3cgpd x 0.83 sq. ft./gpd = (,ate sq. ft. tio =L4r4" <br />2. Select width of rock layer (10 feet or less) <br />3. Length of rock layer = area width = Rock Bed <br />1 LJ sq. ft. + i h. q_ ft. <br />iff <br />dth 510 ft <br />F- ROCK VOLUME Lang <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />!�w sq. ft. x r, ft. _ - <br />21 K cu. ft. <br />2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />n i �c cu. ft. + 27 = a 1) cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />cu. yd. x 1.4 ton/cu. yd. = `? v tons. <br />F. ADSORPTION WIDTH LLA 4( 1..01? w1 <br />I. Percolation rate in top 12 inches of soil is w, mpi <br />2. Select allowable soil loading rate from table; <br />gpd/ft2 <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br />1.20 gpd/ft2+ -; gpd/ft2 = , v <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />x i ", ft= ft <br />.J <br />P.•d.�mR.r <br />tws■,r. .c• <br />Soil Texture <br />c <br />�� w. <br />�.... <br />, r' <br />Faster than 0.1 <br />Couse Sand <br />120 <br />1 <br />0.1 to 3 <br />Sand <br />120 <br />100 <br />0.1 to 3 <br />Fine Sand- <br />0.60 <br />2.00 <br />6 to 15 <br />5WWy Loam <br />0.79 <br />1.52 <br />16 to 30 <br />Loam <br />0.60 <br />2.00 <br />31 to 45 <br />Silt Loam <br />030 <br />2.40 <br />46 to 60 <br />Cla Loam <br />0.45 <br />2.67 <br />61 t0120 <br />Clsy <br />024 <br />3A0 <br />Slower than 120 <br />CL <br />-- <br />-SW tic""s Rme" of fim O•!yr-E <br />.J <br />