Laserfiche WebLink
A. Determine pump capacity: <br />Gravity Distribution <br />I. Minimum suggested is 600 gallons per hour (10 gpm) to stay ahead of <br />water use rate. <br />2. Maximum suggested for delivery to a drop box tlf a horne system is 2,7{1(1 <br />gallons per hour (45 gpm) to prevent build-up of pressure in drop box. <br />Pressure Distribution <br />3. a. Select number of perforated laterals <br />b. Select perforation spacing - *S ft. <br />c. Subtract 2 ft. from the rock laver length. <br />cL Determine the number of spaces between perforations. <br />Length perf. spacing = AL fi. + 3 It. spaces <br />e. _Z42- spaces + 1 = 17 perforations/lateral <br />L Multiply perforations per lateral by number (if laterals to <br />t total nunnber of perforations. <br />X -L- _ prrforations- <br />tiwT. �.,00 ,l <br />g. .Z -/x • _am� ' gpm. <br />SELECTED PUMI' CAPACITY -51 gpm <br />B. Determine head requirements: <br />1. Elevation difference between pump and point of discharge. <br />d feet <br />2. If pumping to a pressure distribution system,add five feet for pressure <br />required at manifold <br />S feet <br />3. Friction loss <br />a. Enter friction loss table with Fpm and pqv diameter. <br />Read friction loss in feet per IW fLvt from wFdr. <br />F.L. = Z•Ok ft./100 ft of pipe <br />b. Determine total pipe length from pump to discharge <br />point. Add 25 percent to pipe length for fllttng <br />loss, or use a fitting loss chart. Equtvolrnt pipe <br />'cngth ' 25 times pipe length = <br />o _ x 1.'_'5 = S't, feet <br />c. Calculate total friction loss b; multiplying <br />friction loss in It/ 100 ft by equivalent pipe IcnFth. <br />Total friction loss - �St7 x _2t__i?-+IW = / -. feet <br />4. Total head required is the sum of elevati(m Litffcrcncc, <br />special head requirements, and total friction loses. <br />111 42) (3c1 <br />TOTAL NEAT) 1 feet <br />C. Pump selection <br />I. A pump must be selected to deliver at least zz gpin (Step A) <br />with at )east feet of total head (Step li). <br />E110 PrprORATION OF ► P[rMOn►T[D L►T[R►L <br />/- <br />C. w Co- <br />iNM.I r� <br />l.ro .I G.L..r.. POW a IV 1.. <br />q <br />L.nSW Loiw w► wiles M �.! r Lew �.w.N <br />.••. V saw <br />P., W..+• Chow*ft coo POW ft# <br />ISM VMq.r <br />64�!w fri�11� �.,L .1 Nes. L.t., <br />P.-I.G.- UK." .1 <br />two. SW Lapp Mow...1 L.." <br />..1 W <br />oayr.l UN ....+ry S &Jr 4 <br />DOW. 11w..y Sow. L,..w <br />TAOIT or f [RroRAT1oN VISCI IARCr51N CIV <br />1fe.id I'crfuratiundla"tat0rcMsl - <br />I0 <br />0.69 <br />1,0A <br />O.S6 074 <br />15 <br />069 040 <br />2 Ob <br />060 1 W <br />25 <br />034 117 <br />30 <br />046 1.23 <br />40 <br />1.13 1.47 <br />so <br />1.26 165 <br />aUv 1.0 <br />bUse 2 <br />foot of head for rrudernttal sy-men-S <br />0 feet of head for other establishments <br />Plpc Lcrph <br />Point or TDischarrc <br />Elevatilm Diffcrertccl <br />1'untp <br />F 18b <br />1.S Inch 2 o I h 3.01r,.h <br />pen rr a w ► tm h or p.,w <br />I0 <br />0.69 <br />0.20 <br />12 <br />0.46 <br />0.28 <br />14 <br />1.28 <br />0.38 <br />16 <br />1.63 <br />0.48 <br />IS <br />2,03 <br />0.60 <br />20 <br />2.47 <br />0.73 <br />0.11 <br />25 <br />3.73 <br />1.11 <br />0.16 <br />AIL <br />15 23 <br />1.55 <br />0.23 <br />S0 <br />790 <br />2.06 <br />0.30 <br />11.07 <br />: 64 <br />0.34 <br />45 <br />14.73 <br />3.28 <br />1 049 1 <br />50 <br />3.99 <br />G.36 , <br />55 <br />4.76 <br />071 <br />60 <br />S 60 <br />0 82 <br />