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1993-07-12 Septic System Site Eval & Testing
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1400 Bracketts Point Road - PID: 11-117-23-32-0025
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1993-07-12 Septic System Site Eval & Testing
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Last modified
8/22/2023 3:30:03 PM
Creation date
4/5/2023 3:16:24 PM
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x Address Old
House Number
1400
Street Name
Bracketts Point
Street Type
Road
Address
1400 Bracketts Point Road
Document Type
Septic
PIN
1111723320025
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I.J. vv.. - ---•-..— -„•..--..--- <br />1. If landslope is 3% or more, subtract rock layer width from <br />adso►ption width to obtain minimum downslope dike toe for <br />absorption: <br />�ift-�v ft=Meet <br />2 <br />Calculate minimum mound size based on geometery: <br />37 <br />a. <br />Determine depth of clean sand fill at upslope edge of rock <br />6.1 <br />21.1 <br />layer. Separation feet <br />W <br />b. <br />Multiply rock layer width by landslope to determine drop <br />71.1 <br />OA <br />in elevation; Slope Difference <br />�•-�— <br />u <br />/O x 3 % + 100 = b- 3 feet <br />'-'*-- <br />c. <br />Add depth of clean sand depth of clean sand for <br />"�'�” <br />so <br />separation at upslope edge (2a) to depth of rock layer to <br />7J <br />u <br />rock depth and the depth of cover to find the total mound <br />IO <br />LU <br />height at upslope edge of rock layer; <br />670 <br />I <br />� ft + I ft + l ft = _ feet <br />Im <br />d. <br />Enter table on page bottom with landslope and upslope <br />LS1 <br />711 <br />dike ratio. Select dike multiplier of 41 <br />L/ <br />170 <br />e. <br />Multiply dike multiplier by upslope mound height <br />I,l5rc1o1. 30 ; C,-7!5- <br />-7Sto <br />all <br />&A <br />toget upslope dike width:416- x 3 =13 feet <br />3,13111(.= 2: 14erz- <br />f. <br />Add the depth of slope difference (2b) to the upslope <br />X312-"'.'1.12sog <br />L!0 <br />Ld <br />downslope <br />height to get the downslope hei ht <br />3.tjillOX 1'3 = Zte <br />an <br />3 + or3 <br />g4�5 ,may <br />g. <br />Enter table on page Luttom with landslope and <br />140 <br />downslope dike ratio. <br />Select dike multiplier of S& <br />L" <br />h. <br />Multiply dike multiplier by downslope mound height <br />79 <br />La <br />to get downslope dike width: • ' 88 x 3.3 = Zo feet <br />LA <br />i. <br />Compare the values of step G.1 and Step C .2.h. Select the <br />in <br />to <br />greater of the two values as the downslope dike width; <br />L/ <br />5n <br />2Z feet :,:: ; : :'• t v:�::: �r: :::::t::r :t::;: ;:::::t . <br />L. <br />Total mound width is the sum of upslope dike Dad %4Qd;' <br />:r •.y .Y.Y •r.Y Jti Y r t Y.Y L::.'tt <br />• <br />9i5 <br />width plus rock Iayer width plus downslope <br />f{i'tiit +t{ <br />3a <br />dike width;` <br />V.y.t4�.-'Y{�.v.u. v.4. •r. <br />L" <br />.v:'•rt'.•.Lr:; <br />1_ ft + 10 ft + � ft = 4-3 feet vr-,-v:omM+;:M= <br />r` V <br />.fi(r rtir r�J:L••:J_►�} OS>r:w~M__ <br />417 <br />k. <br />k. <br />Total mound length is the sum of upslope <br />.tit�.tYY. <br />;::If•it.rtti: <br />:.: :rf '.'J, ,::,:r.•r •t, •._;:t;;;:f..{::; <br />(fie Wid16 <br />17.13 <br />1N <br />dike width plus rock layer length plus <br />r <br />_,• <br />, k.�•Z:;y,�iM ?{. <br />J.L yrtihr{��: <br />'.4�Y:y• <br />4.9 <br />upslope dike width, :ti• rt:: <br />''Y.�.:'.'.�' <br />..t ryl r. .Y�Yfr••. <br />�' ': J :tti Y:.: �Y.: ti •fir: <br />LO <br />13 ft + 50 ft + 13 ft - �� feet <br />37 <br />w <br />1a <br />6.1 <br />21.1 <br />391 <br />W <br />41 <br />71.1 <br />OA <br />• <br />7a <br />u <br />za <br />Ln <br />7.0 <br />1r <br />u <br />so <br />u <br />7J <br />u <br />1 <br />IO <br />LU <br />Sri <br />670 <br />79 <br />111 <br />Im <br />all <br />SY <br />LS1 <br />711 <br />: <br />L/ <br />170 <br />4.35 <br />C% <br />LY3 <br />7.33 <br />all <br />&A <br />Lo <br />L77 <br />L" <br />LU� <br />170 <br />is <br />L11 <br />L71 <br />L!0 <br />Ld <br />/ <br />SAI <br />an <br />���!!! <br />7JLim1 <br />on <br />l <br />140 <br />ar <br />L" <br />LAS <br />5 <br />79 <br />La <br />LO <br />LA <br />1077 <br />LAI <br />in <br />to <br />•a <br />L/ <br />5n <br />L <br />L. <br />5.10 <br />7.14 <br />9i5 <br />IL07 <br />23+ <br />3a <br />3.00 <br />ut <br />L" <br />LAI <br />7 <br />I= <br />5.Y <br />7r <br />1673 <br />17.13 <br />1N <br />L2 <br />170 <br />4M <br />4.9 <br />L13 <br />0 <br />LO <br />La <br />L33 <br />1153 <br />L"I <br />L41 <br />LO <br />39 <br />aO <br />LN <br />l/ <br />1 <br />4.11 <br />L21 <br />ID <br />IIDS <br />1L57 <br />3.36 <br />Lf1 <br />145 <br />110 <br />470 <br />&au <br />as <br />LO <br />IOD <br />Is= <br />311 <br />3-71 <br />L00 <br />331 <br />175 <br />" <br />LU <br />W <br />it <br />w <br />734 <br />11.11 <br />1715 <br />AA3 <br />L3L <br />US <br />in <br />u1 <br />1M <br />SSI <br />12 <br />aa <br />?A <br />1750 <br />11.41 <br />4175 <br />L21 <br />L70 <br />112 <br />lA <br />In <br />a,0/ <br />
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