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nn r�n•rnt r�iCT'T2iRIi-T'TDN SYSTEM <br />1. Select number of perforated laterals <br />2. Select perforation spacing = _5 feet <br />3. Since perforations should not be placed closer than 1 ft. to <br />the edge of the rock layer (see diagram), subtract 2 ft. from <br />the rock layer length. <br />-- 2 ft. = _T feet <br />Roa Ter W" 8, <br />4. Determine the number of spaces between perforations. <br />Divide the length above by perforation spacing and round <br />down to nearest whole number. <br />I <br />Length perf. spacing = ft. y 2)f I. = Zo spaces <br />S. Number of perforations is equal to one plus the number of <br />perforation spaces. <br />go spaces + i = 21 perforations per lateral <br />Multiply perforations per lateral by number of laterals to <br />get total number of perforations. <br />A 21 = � perforations <br />Iasaral s pars L~W <br />7. Determine required flow rate by multiplying <br />number of perforations by flow per perforation <br />&3 x�=Zgpm. <br />If laterals are connected to header pipe as shown on upper <br />example, select minimum required lateral diameter from <br />table 2; enter table with perforation spacing and number <br />of perforations per lateral. Select minimum diame r for <br />perforated lateral = inches <br />CW PEWORATIOW Of A POWORATM LATCRAL <br />lVw Cw <br />r 7— .T <br />L.V- .l deems. I.0r4 I. a✓' <br />Luw•~�rwM mom•• aww <br />I•a.r.�aaw W Th wrua+wut <br />b: <br />An L.... Q* 16" <br />.1 4.0 L.W <br />►r aa.•1.r1. t..•1•.a •1 <br />Dow i-. U� Mlr•w N UNn1 <br />o.grn s.0 /..wa► s.�m.. <br />a•w• I••o.� S..I L...r <br />TABLE OF [ LRFORATION OLSCHARGFS IN GPM <br />Heed Perforation dlarnater (inches) <br />lard Y /rW .1 <br />r/} <br />r/• <br />lab <br />036 <br />0.74 <br />0.69 <br />0.90 <br />16 <br />0.30 <br />1.04 <br />15 <br />0.89 <br />1.17 <br />3-0 <br />0.98 <br />128 <br />4D <br />1.13 <br />1.47 <br />SD <br />1.26 <br />145 <br />a Use 1.0 foot o(head for residential systems. <br />b,Um 2 0 (cet of head (or other establishments <br />Irshlw 2 <br />Maa+� dlaedMaMs�� of �r irad MefentM� N <br />� rral(ast+� <br />lard Y /rW .1 <br />•-+ cwt 1.25 inch 1-5 inch 2.0 inch <br />2.5 14 <br />18 <br />8 26 <br />3.0 13 <br />3.3 12 <br />16 <br />25 <br />4.0 11 <br />15 <br />23 <br />5.0 10 <br />14 <br />22 <br />9. If perforated lateral system is attached to manifold pipe near <br />the center, As in lower example, perforated lateral length and <br />f--_hnumber of perforations per lateral will be approximately one (f--- <br />half <br />alf of that in 11' 6. Using these values, select minimum <br />AZ <br />diameter for perforated lateral from table 2 <br />perforated lateral = %, S inches <br />r <br />