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MOUND DESIGN WORKSHOEl' <br />(I'or Flows up lo 1200 gpd)1 <br />A. FLOW <br />Estimaled <br />or measured <br />. gpd (see pages D-7 or 1-3,4,5) <br />_ gpd X 1.5 =_____________. <br />B. SEPTIC TANK LIQUID VOLUMES <br />Ballons (scgallons (see j^ages C-3 or C-5) <br />Z3 <br />C. SOILS (refer lo site evalualion) <br />1. Depth lo reslricling layer = <br />2. Deplh of percolation tests = <br />3. Percolation rale ^7 <br />4. Land slope _ <br />______inches <br />/'J- inches <br />13 <br />inpi <br />lUtinialcil Sewage l*kmt in (iallimf pa day <br />(gpd) <br />Number <br />of <br />Urdrcafinc <br />Typel Type II T)|ic 111 <br />2 3()0 225 IRO <br />3 450 300 21H 611% <br />4 600 375 2Vi el !)(• <br />5 750 450 294 valict <br />in <br />6 900 525 332 YJ-7 1050 600 370nl?00 675 4 OR III <br />cnlumw <br />Srplk lanh rt|iM In <br />Numivr of Mini/iium 1 iqtfiil Liquid capni ity «iih <br />llrtlionmi ('•l*aciiy gathjfc di«p«i««| <br />2ih Irii 7 50 IIM <br />1fw4 Kill IVl) <br />4of 6 15411 J250 <br />7.lw9 2(11)RID <br />over 9 <br />\ <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rale by 0.83 lo obtain required area of rock <br />layer: Daily Flow x 0.83 = <br />gpd X 0.83 sq. ft./gpd = IVl sq. fl. <br />2. Select width of rock layer (It) feet or less) = / O ft. <br />3. Length of rock layer = Area + Width <br />nh sq. ft. ■' fl. = fl.Rock Bed <br />E. ROCK VOLUME <br />1. Multiply rock area by rock deplh lo gel cubic feel of rock; <br />fl. X / fl. =‘2i£ cu. fl. <br />2. Divide cu. fl. by 27 cu. ft./cu. yd. to gel cubic yards; <br />'Tj JL cu. fl. + 27 = cu. yd. <br />3. Multiply cubic yards by 1.4 lo gel weight of rock in tons; <br />cu. yd. X 1.4 lon/cu. yd. tons. <br />Length ‘ <br />75 ' <br />VVkllh ,Jl0j.L <br />i <br />F. <br />1. <br />2. <br />ADSORPTION WIDTII <br />Percolation rale in lop 12 inches of .soil is 7 inpi <br />Select allowable soil loading rale fn»in table on page E-; <br />- iind/fP <br />AlKMiriillim Wiillli Sl7.lii|>Ttil>lc <br />3. <br />4. <br />Calculate adsorption width ratio by dividing rock layer <br />loading rale of 1.20 gpd/fP by allowable soil loading rale; <br />1.20 gpd/fP + _i_irRpd /ft' = <br />Check Ihis value on }>a^e L- ld. <br />Multiply adsorption width ratio by rock layer width lo gel <br />required adsorption width; <br />Pciiolaiioti Kale <br />ill Mimitc« |*cr <br />liKh (MPI) <br />Soil Tciiufc <br />('.BlIoMI <br />JH ’I day |»«*i <br />WIII.VC (lN>l <br />Ratio of <br />Ahiotpiion «idih <br />to Koci 1 nyer <br />Widih <br />raM«r than 0 1 •Co;iisc Sand <br />0.1 to 5 Sami 1 20 1 00 <br />0 Uii 5 ••Pine Sam! *•0(4)200 <br />6 lots Sandy Loam 07‘)15?1610 Ul l.onni 014)?m <br />.31 10 45 Sill 1 oain 0.50 2 41) <br />46 hi 14)Clny Loam 045 .2 67 <br />N) to 1 ?0 (lay 0.24 500 <br />Slnvirr than <br />no***Clay