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1993 Septic system design & permit
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1993 Septic system design & permit
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Last modified
8/22/2023 4:35:16 PM
Creation date
1/31/2023 2:03:49 PM
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x Address Old
House Number
2240
Street Name
Abingdon
Street Type
Way
Address
2240 Abingdon Way
Document Type
Septic
PIN
0311723230009
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MOUND DESIGN WORKSHEET <br />(For Flows up lo 1200 gpd) <br />A. FLOW <br />Estimaled ^00 gpd (see pages D-7 or 1-3,4,5) <br />or measured gpd x 1.5 ■____________. <br />D. SEPTIC TANK LIQUID VOLUMES <br />-l-ilSa____gallons (see pagesC-3 or C-5) <br />C. SOILS (refer lo sile evalualion) <br />1. Depth lo rcslricling layer » __Inches <br />2. Depth of percolation tests «____/ _ inches <br />3. Percolation rate V 3 mpi <br />4. Land slope______^ % <br />ruimilfij Sewige Tlowi In Oilliini pit diy <br />(ipj) <br />Number <br />of <br />ncdriKvfni <br />IVpel Ty,« II m <br />2 300 225 IRO <br />3 450 300 218 <br />4 600 375 250 o/u« <br />S 750 420 ’ It <br />6 9U0 525 132 V-7 1050 600 370 l| K <br />III%1200 675 4C8 "1 <br />Icf Ik T^nk In <br />Number of <br />IVo4»0n«ni <br />Xfinunum |.Ii)uh1 <br />Caftcity <br />l.iqultl cnjiKily with <br />Ittbiic Ji.potil <br />lorkM 750 1115 <br />ioi4 lOfi IVI) <br />4 or 8 lS<f)2250 <br />Uor9 <br />0%Cf • <br />2nn 3«0 <br />D. ROCK LAYER DIMENSIONS <br />. 1. Multiply flow rale by 0.83 lo obtain required area of rock <br />layer: Daily Flow x 0.83 « <br />^DO gpd x 0.83 sq. fl./gpd = iSO sq. ft. <br />2. Select width of rock layer (10 feel or les.s) = / P ft. <br />3. Length of rock layer» Area + Width = <br />n’^0 sq. ft. + JQ__ft. = yy ft. <br />E. ROCK VOLUME <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />ISP sq. ft. x / ft. = X^cu. ft. <br />2. Divide cu. ft. by 27 cu. fl./cu. yd. lo get cubic yards; <br />ySPcu. ft. + 27 s cu. yd. <br />3. Multiply cubic yards by 1.4 lo get weight of rock in tons; <br />cu. yd. X 1.4 ton/cu. yd. »39 tons. <br />Rock Ded <br />.Vidlh £10 fk <br />1 <br />F. ADSORPTION WIDTH <br />1. Percolation rate in lop 12 inches of soil i.s mpi <br />2. Select allowable soil loading rale from table on page E-; <br />■ ^ gpd/fP <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rale of 1.20 gpd/fP by allowable soil loading rate; <br />1,20 gpd/ft* + _j:i_ gpd/fl^s -a?, ___• <br />Check this value an E-16. <br />4. Multiply adsorption width ratio by rock layer width lo get <br />required adsorption width; <br />3.-/X <br />Ati.inrpliou WltlMi Slzlni;Tnb!c <br />KrcuUiliin Raw <br />III K^iiiuiei per <br />liich^MPn <br />Sod Tcaiufc <br />Oaibiii <br />|Kf day pCf <br />kluarc fiM>i <br />Hallo of <br />AMnipiIrm widih <br />III Layer <br />Wuliti <br />Pieter tilth 01 •COaiM .Saiul <br />0.Mu5 I 20 1.00 <br />O.I lo5*‘Pine SaiMl ••OCO 2fO <br />6 10 IS Saiuly Lntin 0.79 !.52 <br />I6I0.3Q I.OthI 060 2liU <br />31 10 43 Sill t,oim 030 2.4Q <br />46 lo 60 Clay Loam <br />CUy <br />045 267 <br />60 to 1211 024 5.1W <br />Slo«^cr thin <br />I20*** <br />Clay
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