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]PR�SSURE �ISTRT�UZ'ION 5y5T�IVI �
<br /> �
<br /> GeofexHle fabric
<br /> l. Select number of ..:..•.,,, y..e�:�•.. .a. , '
<br /> Perforated 1 als 3 ���.�:;�. � dy?.J.+?':d�st'. ' p" e;�
<br /> ater .::4:-. , t;*� .SU3.o:..,;tU;�tn��` ,c,'�.n;ur.',`,'T�n.n:.,t,v7a�.�;-,;.,s•
<br /> _ • -.. .. M-o.T.o•,.:�;,�r.:�.c�.s;��;l.-o`- ._r�pl;,l:r
<br /> arterinch erfocaHonss aced� ° ""���" �%•'ra�
<br /> 2. Select `�:-: . . s� �;,�.�,�t�;i.�'
<br /> �'':'���'r,:!i���r4F,.'- . r;�: :c�.°� �, f2�:�ta,.;,,
<br /> . <� r�,il �,.� �c:.�;.:"
<br /> erforations ��p:'%ia Z �P:'�,�0' w,��^C'
<br /> - � pC1�.'�g= �e� f'ee�. �. C:�U`':��F.�,�:.�S:,:r.5-�c )�J,'�d�.. �.. n .`r�.�O..�r..5�:,,:f:f,.'�o'o}:r.i!1��..
<br /> . -----__. -,:,;...�i;mh,:.�_c�.h:,rrGxl�'_:�,�y.,�p;�- :;:�},.t3�`� r;�.�ri-::.,�,� "o�r,
<br /> i!LU�:��1'� Q" ii:.•'� Jio+o�c.r.:��� '< 4��.,rr,�n,nl)C;bl��,t.."�:�
<br /> . ir .�. -n :. i,_: . . G„J:t:�.
<br /> .o.;;:r.�:,.:o..1?r,:��r'�'c:r�y;9s':6.v 1°:'�°1�c�� ;: , : ;.,�.,,�.�
<br /> n , .s�3(r,�.r,:;,�:,�,,,. ;r,ee;�:o
<br /> 3. Since perforations should not be placed clo�er tlian 1 . to� Perf sPa�i�g l.s,-5• G I,1 '� .
<br /> Perf Sizing 7/32"-1/4"
<br /> the edge of the rock layer (see diagrarri), subtract 2 ff, from
<br /> the rock layer length. �,__ �
<br /> Perfo�atlon dtscharges(n gpm
<br /> °� a = �g -2 ft• _—�"�_feet, perforatlon dlameter
<br /> � � head� inches
<br /> �. Determine the number of spaces between perfoz�ation . (feet) 1/8" 3/16 7/32 1/4
<br /> Divide the length above by��rforation spaculg and r tu-icl �'�° 0.18 b.42 0.56 0.7n
<br /> down to nearest whole numb�r. 2.0b
<br /> � 0.26 0.59 O.f�O 1.04
<br /> Lengtli perf. s acin a � 5•0 �•�� 0.94 1.26 1.b5
<br /> P g= 3�i ft. � "`'� ft. == 1 "'.:� s �ace � a
<br /> • . (3� ��` � UsA 1.0 foot for sln�le-famlly homes,
<br /> � � b Use 2,0 feet for anylhing else.
<br /> 5. NLunber of perforations is equaT to one plus.the numb i of ' POtentlol}or �� ,�
<br /> P 99 8
<br /> perforation spaces _
<br /> _ .�
<br /> �{. '
<br /> =spaces + 1 = ) � pe�gmiations/1��ex•a1 Maxunum number of quazter inch perforations pei
<br /> . lateral to guarnantee<10%discharge variahon
<br /> �- Muliiply perforations per Iateral by ntun.ber of lateral t0 � PS facingn /
<br /> get total number of.perforations. . �feet) 14 . 1� �
<br /> �-5 1`� 28
<br /> atera X -1-�—�__ H�z..- erfopations: . � 3.0� �
<br /> per s aler � n�
<br /> �—�__.,._____,_..._ ._................
<br /> .C.
<br /> Calculate the square footage pei perforatic�n (6-10 sqft/ erl.) [�,0 �� �-6 �5
<br /> system area: 1 p . x �.y-� _ ��► � . . 11 15 23
<br /> u�� 5.0 10 14 22
<br /> area er o o„� –���_s�yftlperf � . .
<br /> 7- Determule required flow rate b '"""'�°`° �°�^�° ^r �� Of` PAE551ME OIST}j�BUiION nnE�,
<br /> � number of perforations by.flo peruperforation �
<br /> . � r,'�n
<br /> a � �GF�
<br /> , �� �
<br /> � X SP� per —'=-a--��nl • '�
<br /> . . j.,.,rr.'
<br /> /
<br /> 8. Tf laterals are connected to header pipe as slzow�1 ori iip eT �� „�n�'"'���� ����PJwJ�
<br /> example, to seZect ininimum required lateral diameter; e ter ��
<br /> table wit�z perforation spacing and niunber of perforatio s
<br /> per lateral. Select mini�z�nurn diameter for � �-���F����DMiEO�IpE UTEflA�S,��
<br /> PnE9lWiE O19Tf�leu�lON YI A
<br /> perforated laferal – � �2 inch�es, r.(""/P9R"'1°���<<Mr 'ou•,o
<br /> ``—rartro�una�e a.i+ao�.• ^M��
<br /> . 9. If Perforated lateral systeni is at�ached to n.ianifold pipe ear. E� �M1�S�Y��(�ro~
<br /> the center, lower dia am ��sMr�`.a roy« r.�,.��,o
<br /> �' ,perforated later�l length anci '�rt ,,,,
<br /> number of perforations per laferal will be��pro�atel� one .
<br /> half of that '-��'r,:�•;z���°�.�
<br /> in step 8. Using these values,s�lect mini�triu ",�� �.\
<br /> .. �"�`"�, ,s���,��
<br /> . �eo^N�p.�NEn�
<br /> diameter for perfoY�ated lateral�����h��. , w.�„
<br /> � . .. .
<br />
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