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. � � MOUND llESIGN WORKSHEET <br /> � � (Por Fl�>ws up to 1200 gpd) <br /> A. FLOW listimatcd Sew'age Pbus in(ialluns pv Jap <br /> ____�— g� p g csr�) <br /> Estiiilated y f� ��� (see a es D-7 or I-3, 4, 5) humlx�r <br /> or measured g}�d x 1.5 = �r -r���i ry��:u �y�ui r>rx <br /> licdrooms ��� <br /> Z 300 225 IRQ <br /> I3. SEPTIC TANK LIQUID VOLUMES 3 aso �a� zis o�� <br /> 4 GOQ 375 25G ���, <br /> � 5 750 450 294 �„ <br /> /- )�g�.� �-/o^�(i�,�.,;r�allons (see pages C-3 or C-5) 6 y�, s2s 332 ��a�. <br /> � �� <br /> 7 IOSO GW 370 ��� <br /> 8 1200 G7S 408 cdw+re <br /> C. SOILS (refer to site evaluation) <br /> ticylic Tan4 Cap.cil4•�iu grilone <br /> 1. Deptl� to restrictinb layer = .'� iilclles <br /> Numbcr of Mininmm I.iquiJ I.�quid r prciiy with <br /> 2. Deptll of percolatioil tests – i�.. IIlC11�S it"d`°""': c'�"'ry ¢"b:'�;`�'"�„"i <br /> 3. Percolation rate ,��5' Z°`�"' '�° '�� <br /> I11�71 7�,a �pxi �5�x� <br /> a�.� �xK� zuu <br /> 4. Land slope cn % �.A o�9 u�«� xxx, <br /> nrcr 9 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate t�y 0.83 to obtain rec�uire��i area of rock <br /> layer: Daily Flow x 0.83 = <br /> �(c�� gpd x 0.83 sq. f t./gpd = 3 7�.Ssq. f t.= `��O <br /> 2. Select widtll of rock layer (10 feet or less) _ /O ft. <br /> 3. Leilgtll of rock layer = Area = Wi�itll = <br /> ��_ sc]. (t. = /L� ft. = Y�=� ft. Rock I3ed <br /> �J� T <br /> .' �v�d�n siu<<. <br /> 'f' 1 <br /> E. ROCI< VOLUME �--��et�6tt, —+ <br /> l. Multiply rock area by rock depth to get cubic feet of rock; <br /> ��sq. ft. x_L ft. = o� cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �� cu. ft. = 27 = ��{,�cu. yd. <br /> 3. Multiply cubic yai-ds Uy 1.4 to get weiglit of rock in tons; <br /> (�� cu. yd. x 1.4 ton/cu. yd. _ � tons. <br /> F. ADSOIZPTTON WIDTH <br /> 1, P�I'COIat10Il I'dt2 lIl l0�) 12 inches of soil is c�� IIl��I ���s�rptiun��'idtli SizinK'1'aUic <br /> Pcrcol�iiva Raic Gnlluns Iialio nl <br /> 2. Select allowaUle soil l��ading rate froin table on page E-; inMinutcs��cr SoilTcxwre ,x„�:�y,�� Ahcorpiionw,,,��, <br /> Inch lMl'I) syunre fai� io Rcxk L:�ycr <br /> ,G b gpd/f tz �ti-������ <br /> 3. Calculate adsorption �vidth ralio by dividing rock layer F-���«��,���o., • c���us�,K, ..-.- ..-._ <br /> o.i��s s���� i.zo i.00 <br /> loading rate of 1.2U gpd/ft' by allowable soil loadiilg rate; o_���s�• r��,rs��,�•• o�o z�� <br /> G to I� Snndy Louin OJ9 1.52 <br /> 1.2U gpd/ft2-� , i.!' d/ftz= �-�o i����o ���, _o.�o z.�x� <br /> gP JI 1015 Sil�Loam 0.50 2.40 <br /> G�eck tltis z�nlue oit }�n�'C �-��7. 4�+���� ClayLoom 0.45 2.67 <br /> � �o izu ciay o.za s.uu <br /> 4. I��Iultiply adsorption width ratio by rock layer width to get s�o�o,..a� c��Y .._._ .._._ <br /> required adsorption widtl�; <br /> , o x /'b ft = ab ft <br /> � ._ <br />