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ii3,%1�Ji J%, 11:15 F:IY 61���75ii11 S P TESTINc; INi; �����
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<br /> f�' PT lM'P .�fj,�,,CTTON PHO ED 1�E
<br /> f►O PCFiFCi7�AT10H OF ♦ PERFOQITFG IiTEF:.4
<br /> ,� Detes�uii.ne pump capadry: ���
<br /> GraviFy Distribution r....�
<br /> j. Minimurn sugge�sted is 60Q gallons per hour (14 gpm) to stay ahead of ;:.-.���- � - � ,,`,,,,,w f1e,k ,,,,,,.
<br /> wati2r uSE�`dtP. �r���,e��,.�.o,�.��.�..,.w
<br /> y�...`^^"0�� i
<br /> �. Maximum sug�s. delivery ta �drop box of a home syscem i$2,70� ^•�.�� d����,.P��,
<br /> titi[� �s fw
<br /> gallor�s per ha �5 gpm� o prevEnt build-up of pressure in drop bax. , �,•,,�, ; -� �_,� �:��. ���.
<br /> fl.�a •r A.,.J.«
<br /> . . {Yr'ti�l��W I N�I
<br /> pressure Dis�bution ��^'�� ""-`� "„"'
<br /> 3-a. Selert number of perforated laterals
<br /> b. Se1�t p�erforati4n spacing= feet �r."►:r.'`sw,;,:"�`
<br /> t. 5ubtracK 2 Ft Et+3m the rpck lay�r length.
<br /> ����-2ft� = feet
<br /> d. Detemttne the number oF spaces bet�veen perfOrations.
<br /> Length �rf.5pacing o ft.+_____ft.= spaces Rsyuited Perfor�tian��r
<br /> e. spat�es+ I = perforzGons/latera! � �+��"'P�u"7"'�`t�`f
<br /> F. Multiply perforations per lateral by number oF lacerals ta H�d° ��,,,,�, � a��,
<br /> get total number of perforations. W�a� x �,-��= p�rforatioas. �f�
<br /> g� -� x �"�'`_ ��- 1.Oa 0.56 0.74
<br /> SELECT'EI�PLTI�� CA.PACTI�'�_gpm Yr)AJZ �,OU O�SO �.O4
<br /> �_ Determine head nquiremenfs: a.C.Jse for singie tamily homes
<br /> 1_ Elevation differencebetween pump and point of discharge. b. Use for all other applications
<br /> �,�- feet
<br /> '� 2. If purnping to a pressure distribveon system,five feet for pressure
<br /> required at manifold if gravity system,zero.
<br /> r" feet
<br /> 3, Friction loss
<br /> a. Enler friction loss table with gpm and pipe diameter. ¢'��-�'sil''
<br /> R�ad ficrion loss in feet per 104 feet from table. � PoCn�of G'sch�
<br /> F,� = 3.�.� ft./104 Ft oF pipe 7"=�=
<br /> b. Det�mine total pipe length from pump to discharge IIevaeon�?iFfe-t�cc �
<br /> p�int Add 25 perc�nt to pipe length for Fitbng p„�p �. 7�*
<br /> loss,or use a fitting loss chart. EGuivalent pipe
<br /> length- t.?5 times pipe length� F•ieb
<br /> �_x 1.25 = 1.1 � E�� 1.5 inch 2.0 inch 3.4 inch
<br /> c_ Ca.iculaEe to�l Friction loss by multiplying � r7+as�•,loa a�iaon ap��:
<br /> Fne�on loss in ft/100 ft by equivalent pipe lengch.
<br /> Total fri�tipn loss= ��j.x l )�+100=��_feet 12 4.96 0,:,8
<br /> 4. Tatal head required is the sum of elevation di�ference, 1a 1.26 4.38
<br /> special head requirements,and total fricdon lOss. 16 1.63 0•a8
<br /> 1$ :.03 0.60
<br /> 26 2.47 0.73 8.11
<br /> a� + - + � �s 3.73 �,�� o.,b i
<br /> (1} (2) (3r) 34 5.23 1.55 0.23
<br /> 35 7.90 2.06 0.30
<br /> 40 11,07 2,6s 0.39
<br /> TQTAL HEAD �_feet � ��__ 1a.73 3,2g Q.48 '
<br /> SO 3.99 0 5s ',
<br /> SS 4.76 O.JO
<br /> C. Pump s�lection 60 5.bo o.aa
<br /> � 1. A pump must be selected to deliver at least
<br /> ^.; �_gpm (Step A) with at least a�� . feet of total head (Step B).
<br /> r,-�a-y�
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