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1991 - Septic System Approval
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0820 Old Crystal Bay Road South - 04-117-23-43-0008
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Septic
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1991 - Septic System Approval
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8/22/2023 3:12:31 PM
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x Address Old
Address
0820 Old Crystal Bay Rd S
Document Type
Septic
PIN
0411723430008
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a , <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW ( / ,��������� Estimated Sewage FFlows low)In Oalions per day <br /> Estimateu loo©gpd 1 �'`a <br /> or measured x 1.5 = gpd. "Oo�` Toe I ,yoe 11 Type tit Type <br /> Bedrooms Iv <br /> B. SEPTIC TANK LIQUID VOLIiJMES 2 300 3 225 zeR <br /> 0 1,yr �- <br /> 4 600 375 256 °;lam, <br /> - --- /c) Q gallons /� .�5tc t.(� <br /> 5 750 450 294 M <br /> 6 900 525 332 VV. <br /> 1050 600 370 nt <br /> 8 1200 675 408 colv..m <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer= `f inches Sepik'Mak Oqudtis.{ngallons <br /> 2. Depth of percolation tests = 7,;)-- inches Number of M1nlnwo.Liquid LIqukl capacity with <br /> B.J°°to. Capacity pottage ditpuwl <br /> 3. Percolation rate mpi 2ar1m 730 1123 <br /> 3 or 4 1000 1303 <br /> 4. Land slope U % ,4; M, 22303000 <br /> over Y ----• <br /> D. ROCK LAYER DIMENSIONS <br /> ' 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x0.83 = pi- <br /> Z(rc^c� gpd x 0.83 sq. ft./gpd rlS sq. ft._ /` �G .. .j�� <br /> 2. Select width of rock layer (10 feet or less) = /0 ft. • <br /> 3. Length of rock layer = area+width = Rock Bed <br /> .. Sc; sq. ft. + /a ft. _ !,i5 ft. ,.,.ti.ti.ti.ti.ti.ti.ti. ti•ti•ti.ti.ti•ti•ti. o ,{,4-- <br /> �•r•r•r•r•r•r•r•r•r r•r•r•r.r•r•r•1 <br /> r•r.r•r.r•r•r•r•r•r r•r•r r.r•r•r• <br /> ti.ti•ti•ti.ti.ti.ti.ti.ti.{.ti.ti.{.ti,ti.,.ti:lNidth 510 ft. <br /> r•r•r• .r.rr• •r•r•:Vt.: neare <br /> r r_r_rr_r_r_r.r•_r_rr_r_r_r_r_r_r_r_r r ' <br /> r <br /> E. ROCK VOLUME I Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; ..S <br /> ...tiA <br /> ' ter sq. ft. x /.o ft. = 5 ) cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> Slc� cu. ft. + 27= 2o, i cu. yd. <br /> 'i 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> //o sc./ cu. yd. x 1.4 ton/cu. yd. _-`? tons.d- (0.70 <br /> F. ADSORPTION WIDTH <br /> Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is 13 mpi Permiation Rate Gallant Ratio of <br /> in Minutes per Soll'texture per day per Ahaocpdon width <br /> Inch(MPI) quare foot to Rock Layer <br /> 2. Select allowable soil loading rate from table; - Width <br /> Pasta than 0.1•• Cara Sand <br /> (l' G 0 gpd/ft2 0.11115 Sand 1.20 1.00 00 <br /> 0 I to to 5 �••• PineSanejS_an_d•• 0.60 2.00 <br /> `3t�tr45"161.w, t-o6(L-INzonl m'-'451114 7d0'R 2.02.400 <br /> 3. Calculate adsorption width ratio by dividing rock layer 46 to 60 C1a Loom 0.43 2.67 <br /> 60 to 120 Clay0.24 5.00 <br /> • loading rate of 1.20 gpd/ft2 by allowable soil loading rate; Slower than Cloy --_- _.- <br /> 1.20 gpd/ft2+ U,iC) gpd/ft2 = 2. Cc) 120'.. <br /> • soil loo wane for installation of a <br /> standardsqatom. pa <br /> '• Soil havrirte550%of mote of fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get plaaveryfioesand. <br /> required adsorption width; soil too heavy for installation of a <br /> i standardsystem. <br /> 00 x /0 ft = c�O ft See 7080.0210Subps.A,page 33. <br />
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