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2017-00696 - septic new/replacement
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1860 West Farm Road - 27-118-23-43-0018
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2017-00696 - septic new/replacement
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Last modified
8/22/2023 4:22:39 PM
Creation date
5/7/2020 12:59:38 PM
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Template:
x Address Old
House Number
1860
Street Name
West Farm
Street Type
Road
Address
1860 West Farm Road
Document Type
Septic
PIN
2711823430018
Supplemental fields
ProcessedPID
Updated
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G. DOWNSLOPE DIKE WIDTH <br /> 1. If landsiope is 2.9 % or less adsorption width inculdes both upslope and <br /> downslope widths <br /> 2. Calculate Minimum mound size bsaed on geometery: <br /> a. Determine depth of dean sand fill at upslope edge of rock layer: <br /> Separation y,0 feet <br /> b. Multiply rock layer width by landsiope foot corer <br /> to determine drop in elevation; � ' rove Rd :ed <br /> Slope Difference <br /> Separation _� feet <br /> X %= 100 = feet Slops Dlfforence =1..., et <br /> Upslope Width <br /> c. Add depth of dean sand for separation (2a) -L feet Rock Bed Width <br /> at upslope edge, depth of rock layer (1 foot) to /0 feet Downslope Width <br /> depth of cover(1 foot) to find the mound height at the /(--, feet <br /> upslope edge of rock layer; D.t7 ft+ lft+ Ift= 4.0 feet <br /> d. Enter table with landsiope and upslope dike ratio. ' <br /> Select dike multiplier of t-1 . <br /> e. Multiply dike multiplier by upslope mound height to find <br /> upslope dike width: y x y.0 = 1J feet <br /> f. Add depth of clean sand for slope difference (2b) at downslope edge,to <br /> the mound height at the upslope edge of rock layer (2c) to find the <br /> downslope height; -ft+ -. ft = - feet <br /> g. Enter table with landsiope and downslope dike ratio. <br /> Select dike multiplier of . <br /> D. h. Multiply dike multiplier by downslope mound height to get <br /> downslope dike width: - x h--- feet <br /> i. Minimum mound width is the sum of upslope dike width plus rock <br /> layer width plus downslope dike width; <br /> - ft+ - ft + -. ft= - feet <br /> ....,UDslope Width.. .;;::::;::::::. <br /> fromj. <br /> f • <br /> .' the <br /> minimum width 2 i :::;<:::«:::::::::>:<;<::::>::>::>:::::::>:>::::>::<:>::>:::<::::>::::> ::>>:::>�:::<:> <br /> ub <br /> tract the <br /> S ( ) <br /> ......... ......... <br /> adsorption tronarea (F.4tofind <br /> the <br /> additional <br /> Rock Bed <br /> W1dlh <br /> downslope area for adsorption <br /> a ups] pe width upslope width <br /> - ft- - ft = -feet ; 1h feet _LeL feet <br /> 0 <br /> k. Add the additional width (2.j ) to the <br /> downsolpe width and recalculate <br /> wnsoD <br /> the total width .:. : <br /> _ALL <br /> feetet <br /> �: <:>: ::: . : <br /> l <br /> ft+ )o ft+ to = U z ft feet <br /> 1. Total mound length is the sum of <br /> upslope dike width plus rock layer length ► ' '' <br /> plus upslope -�� <br /> p pe dike width: Total Length <br /> i ft+ SS ft + ),, ft = 49 feet <br /> Downslope Upslope <br /> 3:1 4:1 5:1 6:1 7:1 3:1 4:1 5:1 6:1 7:1 8:1 <br /> S elope <br /> 0 3.0 4.0 5.0 6.0 7.0 3.0 4.0 5.0 6.0 7.0 8.0 <br /> 1 3.09 4.17 526 6.38 753 2.91 3.85 4.76 5.66 654 7.41 <br /> 2 3.19 434 5.88 7.32 8.86 275 3.70 451 5.36 5.79 6.90 <br /> j <br /> 3330 l5{ 5.88 7.32 6.86 275 357 435 5.08 5.79 6A5 <br /> { 3.41 4.76 6.25 7.89 9.72 2.68 3.45 4.17 4.84 5.46 6.06 <br /> 5 353 5.03 667 857 10.77 2.61 3.33 4.00 4.62 5.19 571 <br /> 6 3.66 5.26 7.14 9.38 12.07 2.54 3.23 3.85 4.41 4.93 5.41 <br /> 7 3110 556 7.69 1034 1373 248 3.12 3.70 413 4.70 5.13 <br /> 8 3.95 5.88 8.33 1154 15.91 242 3.03 357 4.05 4.49 4.88 <br /> 9 4.11 6.25 9.09 13.04 18.92 236 294 3.45 3.90 430 4.65 <br /> 10 419 6.67 10.0 15.00 23.33 2.31 2.86 3.33 3.75 4.12 4.44 <br /> 11 4.48 7.14 11.11 17.65 30.43 2.26 2.78 313 3.61 3.95 4.26 <br /> 12 4.69 7.69 12.50 21.43 43.75 2.21 2.70 3.12 3.49 3.80 4.08 <br />
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