My WebLink
|
Help
|
About
|
Sign Out
Home
Browse
Search
01-06-1998 - Fax-Sandd Excav. re:septic info
Orono
>
Property Files
>
Street Address
>
W
>
Woodhill Road
>
315 Woodhill Road - 02-117-23-13-0008
>
Septic
>
01-06-1998 - Fax-Sandd Excav. re:septic info
Metadata
Thumbnails
Annotations
Entry Properties
Last modified
8/22/2023 4:06:25 PM
Creation date
2/27/2020 8:57:02 AM
Metadata
Fields
Template:
x Address Old
House Number
315
Street Name
Woodhill
Street Type
Road
Address
315 Woodhill Rd
Document Type
Septic
PIN
0211723130008
Supplemental fields
ProcessedPID
Updated
There are no annotations on this page.
Document management portal powered by Laserfiche WebLink 9 © 1998-2015
Laserfiche.
All rights reserved.
/
14
PDF
Print
Pages to print
Enter page numbers and/or page ranges separated by commas. For example, 1,3,5-12.
After downloading, print the document using a PDF reader (e.g. Adobe Reader).
View images
View plain text
Jan 06 98 10: 12a Windsor Companies Corp. 482-0607 p. 7 <br /> F-17 <br /> Th <br /> PUMP SELECTION PROCEDURE <br /> 040 PERFORATION OF • PERFORATED LATERAL <br /> A.. Determine pump capacity. <br /> Gravity Distribution <br /> erdou <br /> I. Minimum suggested is 600 gallons per hour(10 gpm)to stay ahead of .+P.'... T <br /> water use rate. i.e..Lee,,,. .. <br /> 4rnr.rnr1 <br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 i',-z^--.•---�..ta ,,,,...„„q.,.,,,, <br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. <br /> Pressure Dtstibution P••••••••1••••,wa« ., <br /> Com.Sari Lever ..'w r""".. <br /> 3.a. Select number of perforated laterals <br /> b. Select perforation spacing= .3 feet if..,,.mt la_ r..,.,,,r,,,,, <br /> c. Subtract 2 ft from the rock layer length. °"�"r"'`"`^" <br /> Rasa,5,�,-2ft = ')-c feet. <br /> d. Determine the number of spaces between perforations. <br /> Length pert'.spacing- 'i c ft.*. z ft.= i spaces <br /> Required Pvfocanon <br /> e. a.y spaces+ 1 = 1' perforations/lateral n gallons cns PminuteDischarge(gprn <br /> f. Multiply perforations per lateral by number of laterals to 9h Dluxazg. <br /> get total number of perforations. L.-7,-T--„,. x �= '7S perforations. ( I ~'"' ; in."...I <br /> g. -2 x -4..=-9-s�>aPm- <br /> SEL£t_1>=U PUMP CAPACITY 4gpm1.Oa 0.56 0.74 <br /> 2.Ob 0.80 1.04 <br /> B.Determine head requirements: <br /> ]• Elevation difference between pump and point of discharge. a. Use for single family homes <br /> feet b.Use for all other applications <br /> 2. If pumping to a pressure distribution system,five feet for pressure ` <br /> required at manifold if gravity system,zero. <br /> A" feet <br /> 3. Friction loss <br /> a. Enter friction loss table with gpm and pipe diameter. Pipe Length <br /> Read friction loss in feet per 100 feet from table. i <br /> F.1.. = 3.0 ft./100 ft of pipe Point of Discharge <br /> b. Determine total pipe length from pump to discharge iyvc <br /> point. Add 2.5pipe length percent to for fitting Elevation DiFicrcncci <br /> Reno /00.c <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length- 1.25 times pipe length= <br /> D x 1.25 = a{ feet F-18b <br /> c. Calculate total fiction loss by multiplying 1.5 inch 2.0 inch 3.0 inch <br /> friction loss in ft/100 ft by equivalent length. ` �""°"t°`per 700 n°`Inca <br /> Total friction loss= 3. t7 x a t .41 00= 1 feet 10 0.69 0.20 <br /> 4. Total head required is the sum of elevation difference, 12 14 1.28 0.28 <br /> 0.38 <br /> special head requirrmeitts,and total friction loss. 16 1.63 0.48 <br /> 18 2.03 0.60 <br /> S + 5-- + / 20 24725 3.73 0.731.11 0.1: <br /> 0.16 <br /> (1) (2) (3c) 30 5.2.3 1.55 0.23 <br /> 35 7.90 2.06 0.30 . <br /> TOTAL HEAD // feet 40 11.07 2.64 0.39 <br /> q5 14.73 3.28 0.48 <br /> 50 3.99 0.58 <br /> C. Pump selection 55 4.76 0.70 <br /> 60 5-60 0.82 <br /> 1. A pump must be selected to deliver at least <br /> -,/ . Ll�gpm (Step A) with at least , 11 feet of total head (Step B). <br />
The URL can be used to link to this page
Your browser does not support the video tag.