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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW D-7 <br /> '---` Estimated ' •,(o gpd (see pages D-7 or I-3,4,5) m '''''t''t"W FLOWS IM ^a Off <br /> WWW4 Vert OF DESIOfJ Z <br /> or measured gpd. =DOOMS t n tEl a <br /> 1 700 B! Ib .0% <br /> 3 410 700 tis •r <br /> • 700 DH 774 ""r <br /> B. SEPTIC TANK LIQUID VOLUMESr moo 270 <br /> gallons (see pages C-3 or C-5) • . m - <br /> W� uaxx3*t_ o Pos C-3 <br /> C. SOILS (refer to site evaluation) <br /> {TRIC TANK CANACIT1q, IN GALLONS <br /> 1. Depth to restricting layer = -ro 3 O inches I , 'am <br /> ,,, a wawa <br /> , <br /> SAL <br /> 2. Depth of percolation tests = inches MUMS /7 ,,,, <br /> 3. Percolation rate I ..3 mpi ! $a• ISIS IN7 <br /> 4. Land slope •078 1.N ».7 <br /> y % r, 0.7 »» t«• <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> gpd x 0.83 sq. ft./gpd = LDS sq. ft.-- Jou,. = c.•csy <br /> 2. Select width of rock layer (10 feet or less) = 10 ft. <br /> 3. Length of rock layer = area+width = • <br /> Li sq. ft. + /o ft. = ft. Rock Bed <br /> 7.574:75.:5:-"74,17.037.5,747:71- <br /> SIO <br /> f.f.f.f,J.f.f• f.r•l•f•f•1.f1 <br /> '''r'f'r ''"f" f'f'jr'f"''j'Width S1O ft <br /> 1•ti.11•ti•ti•b•'ti•ti.ti•M1•ti•ti•ti•ti•ti•• <br /> ,555'555555545.55555455:::::::104 <br /> .f•1•f•r•1•f•f.f•f•f•1.1•!.1• <br /> E. ROCK VOLUME ►-- Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> sq. ft. x ft. = n ' cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> cu. ft. +27= a' cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> al cu. yd. x 1.4 ton/cu. yd. =2.2_tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is ) mpi E-16 <br /> 2. Select allowable soil loading rate from table on page E-16; IL40-�LOAM*huff CP OILS I•• MOWN <br /> • <br /> gpd/ft2 llomM.. Aftiaalia try- <br /> solo elbeml MOT. <br /> miffmaim <br /> 3. Calculate adsorption width ratio by dividing rock layer ""` `"" IA mot <br /> `"r'1 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; ! ,,. .44 CIO 1~ <br /> . .,. ..,. -11.41. L.1 I... <br /> 1. •I •TO ..N W LM <br /> .1 •14 ..N ..N lM t... <br /> 1.20 gpd/ft2+ gpd/ft2= . o . :; • <br /> :: : L;: :» <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a.o x ft= ao ft - <br />