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PRESSURE DISTRIBUTION SYSTEM Geotextile fabric <br /> 1. Select number of perforated laterals � Quarter Inch perforations spaced C 3• u .12,'. <br /> . • • °Crock <br /> 2. Select perforation spacing= 3 ft <br /> Perf Sizing 3/16"-1/4" <br /> 3. Since perforations should not be.placed closer than 1 foot to Perf Spacing 1.5•-5• <br /> the edge of the rock layer(see diagram),subtract 2 feet from <br /> the rock layer length. E-4: Maximum allowable number of 1/4-Inch perforation <br /> per lateral to guarantee<10%discharge variation <br /> RD hyZ��Rg�, -2 ft = L O ft perforation <br /> .spacing <br /> 4. Determine the number of spaces between perforations. <br /> Divide the length(3)by perforation spacing(2)and round (feet) 1 inch 1.25 inch 1.5 Inch 2.0 inch <br /> down to nearest whole number.. 2.5 8 14 18 28 <br /> Perforation spacing= coo ft+ 3 ft= Q o spaces 3,0 8 13 17 26 <br /> 5. Number of perforations is equal to one plus the number of 3.3 1 12 16 25 <br /> perforation spaces(4)..Check figure E-4 to assure the number of 4.0 7 11 15 23 <br /> perforations per lateral guarantees<10%discharge variation. 5.0 6 10 14 22 <br /> ao spaces + 1 = D ) perforations/lateral E-6: Perforation Discharge in gpm <br /> 6. A. Total number of perforations= perforations per lateral (5) perforation diameter <br /> times number of laterals (1) head Inches) <br /> `1 `' (feet) 3/16 7/32 1/4 <br /> a. 1 erfs/lat x '1 lat= t.;� erforations <br /> p p 1.00 0.42 0.56 0.74 <br /> B. Calculate the square footage per perforation. b <br /> Should be 6-10 sqft/perf. Does not apply to at-grades. 2.0 0.59 0.80 1.04 <br /> Rock bed area= rock width (ft)x rock length(ft) 5.0 0.94 1.26 1.65 <br /> 10 ft x !,Z ft= co-zo sqft • a use 1.0 foot for single-family homes. <br /> Square foot per perforation=Rock bed area+number of perfs (6) b Use 2.0 feet for onythina else. <br /> (oma sqft+ (-,*1 perfs= 9.cl sqft/perf . <br /> MANIFOLD LOCATED AT CND OF PRESSURE DISTRIBUTION STSTEI <br /> 7. Determine required flow rate by multiplying the total number of <br /> perforations (6A) by flow per perforation(see figure E-6) W":[•' <br /> 3 ' perfs x 9 gpm/pe fs= 9 7 gpm `� _ <br /> 8. If laterals are connected to header pipe as shown on upper ,,,,,' <br /> example,to select minimum required lateral diameter;enter ..ev'm ' " <br /> figure E-4 with perforation spacing(2) and number of perforations \�"0M <br /> per lateral(5) Select minimum diameter for <br /> LJIYO.tT O/KMMUTIO•Mt LATERALS roe <br /> perforated lateral= inches. MIClMAC DI+TI1DDtION A MOUND <br /> ttIAMMm Mt C M <br /> tt <br /> 9. If perforated lateral system is attached to manifold pipe near �KMtMnM :.-• �` <br /> the center,lower diagram,.perforated lateral length(3) andz"'�'`�' " <br /> Yr�as <br /> number of perforations per lateral (5)will be approximately one `.t.T;ri�;t.,�M.. - -.. <br /> half of that in step 8. Using these values,select minimum •� -• - .-Ia, <br /> diameter for perforated lateral= J`t Z- inches. !t✓ <br /> I hereby certify that have co)npleted this work in accordance with applicable ordinances, rules and laws. <br />