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�)0o W)L`. -;Z:"-V-N ) L.-VI .0 <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flow in Gallons per Day(g; 1) <br /> Estimated 7.S0 gpd <br /> Number <br /> TYpeTip <br /> or measured - x 1.5 = - gpd. Bedroromr le ll type n, tyre TV <br /> 2 300 22.5 180 sot. <br /> 3 450 300 218 •' <br /> B. SEPTIC TANK LIQUID VOLUMES 4 6o0 375 256 <br /> 5 750 450 294 <br /> /-/a.s0 )DOD gallons 6 900 525 332 "`• <br /> 7 1050 600 370 ,dam <br /> S 1200 675 408 <br /> C. SOILS (refer to site evaluation) JSE it Ns>mba "'niman �.''� <br /> 1. Depth to restricting layer = i G 4 1ss 41V inches Bedroomsof , , <br /> 2. Depth of percolation tests = 1 a" inches `'a`' `'"`' <br /> 3. Percolation rate t7.--7 mpi 2 3 et or lea <br /> or 6 1.503 2 7S0 1,125 <br /> 4. Land slope 5 % 7 or a z000 .250 <br /> 3,000 <br /> over 9 Sea hg.C-6 (s 1$) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = <br /> iso . gpd x 0.33 sq. ft./gpd = c.,-a;, sq. ft+,°A,egy <br /> 2. Select width of rock layer (10 feet or less) = /o ft. <br /> 3. Length of rock layer = Lrea+width = Rock Bed <br /> c,<0.4 4 s q. ft. + )o ft. = c,q ft. ? � � f =r,f.f�ff4, �r:ftif41`. ffffff?� rtir1rtir1r.1ti•r�r rtir1•r\rti:.ti•:;:r•~• <br /> width < <br /> 10 ft. <br /> :r1555•55•55555•55555•5•5 <br /> E. ROCK VOLUME ~- Lente _I <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> c.v 9 sq. ft. x).0 5 ft. = '-)ii cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft:/cu. yd. to get cubic yards; <br /> r)1 ce cu. ft. +27= cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> D,,-) cu. yd. x 1.4 ton/cu. yd. = ace tons. <br /> F. ADSORPTION WIDTH �-'- `- 1.'0 A <br /> Absorption W1dth Sizing Lbk <br /> 1. Percolation rate in top 12 inches of soil is_12.7 mpi Percolation Rate CarlavRm..1 <br /> Mims�, Texture inch Soil 4".:7... "''e t <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse Sand 1.20 1.00 <br /> .H gpd/ft2 0.1 to 5 Sand 1.20 1.00 <br /> 0.1 to 5 Fine Sand" 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 163. Calculate adsorption width ratio bydividingrock layer 31 to so Loam 0.60 2.00 <br /> rP Y 31 to 45 Silt Loam 0.50 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loa.iing rate; 46 to 60 Clay Loam 0.45 2.67 <br /> 1.20 gpd/ft2+ ,t_4 s gpd/ft2 = a. L,'7 . Slowe than 120 Clay - - <br /> "Soil luring 50%a mare c fine or icy fine,.and <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> -,i,,-) x 10 ft = at,.2 ft <br />