Laserfiche WebLink
Designed By: August 28, 1998 <br /> Septic Evaivations,Inc. Ann Carpentier <br /> Chanhassen, MM MOUND DESIGN WORKSHEET 301 Willow Drive <br /> (612)470-4024 (For Flows up to 1200 gpd) Orono, Hennepin Co. <br /> Lic. <br /> A. FLOW SWMAW sewage Flow AN auor PW&Y <br /> r <br /> Estimated 450 gpd IV� TW I 0 Type® <br /> or measured x 1.5= gpd. <br /> 21do <br /> B. SEPTIC TANK LIQUID VOLUMES 4 6 0 355 236 <br /> 37 ,9(dw <br /> 10005 75D 450 294 <br /> gallons 6 907 523 332 Typa� <br /> 7 IWD 600 310 <br /> If 1200 673 4M III <br /> C. SOILS(refer to site evaluation) 114- <br /> 1. Depth to restricting layer= 24 inches 2.0 jeet 11 �� <br /> 2. Depth of percolation tests= 12 inches •�+••• � .�.� ..W* <br /> 3. Texture Clay Loam Percolation rate 40 mpi �':: ow is m1S0°oe <br /> 4. Land slope 4.2 % t Ora n a X0 A <br /> EX <br /> D. ROCK LAM DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer.A x 0.83= <br /> 450 gpd x 0.83 sq.ft./gpd= 374 sq,ft. <br /> 2. Select width of rock layer(max 10' if<120 mpi max 5')= 10 ft. <br /> 3. Length of rock layer=area+width <br /> 374 sq.ft.+ 10 ft,= 37 '°�,"�"2�'p <br /> Width 1 ft <br /> <120mpi<10' Length, 37 jt <br /> E. ROCK VOLUME <br /> >120mpi<5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; 374 sq.ft.x 1 <br /> ft.= 374 CU,fL <br /> 2. Divide cu.ft.by 27 cu.ft./cu.yd. to get cubic yards; <br /> 374 cu,ft. +27= 14 cu,yd, <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; 14 cu.yd.x 1.4 <br /> ton/cu.yd.=19 tons. <br /> F. ABSORPTION WIDTH A6aeple.w sols nw. <br /> I. Percolation rate in top 12 inches of soil is_.40 _mpi �a. � �o�. > <br /> Texture Clay Loam ,,4 LM.Sift <br /> F W*MO.l0&INSsa sow IM im <br /> 2. Select allowable soil loading rate from table; 61 a �Sad Q60 <br /> 1-9 <br /> 0.45 gpd/ft2 31 py 3dtLaaam 0.50 22'00iu <br /> 46x60 0%!:: OAS U7 <br /> 6010120 SAI <br /> 3. Calculate adsorption width ratio by dividing rock layer 0' " i to cow 02° 6.00 <br /> loading rate of 1.20 gpd/f t2 by allowable soil loading rate; <br /> 1.20 gpd/ft2+ 0 45 gpd/ft== 2.67 <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> 2.67 x 10 ft= 27 f t p 1997 Melonie LS Elvebak <br /> M <br />