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PRESSURE DISTRIBUTION SYSTEM <br /> Geotextile fabric <br /> 1. Select number of perforated laterals 3 Quarter inch perforations space 12 <br /> 2. Select perforation spacing= 5 ft s'of:.rock <br /> Perf Sizing 3/16"-1/4" <br /> 3. Since perforations should not be placed closer than 1 foot to Perf Spacing 1.5'-5' <br /> the edge of the rock layer (see diagram),subtract 2 feet from <br /> the rock layer length. E-4: Maximum allowable number of 1/4-inch perforations <br /> (o ceper laterd to guarantee d 0%discharge variation <br /> Rock ayer lenger, -2 ft - ft perforation <br /> 4. Determine the number of spaces between perforations. spacing <br /> feet 1 Inch 1.25 inch 1.5 inch 2.0 inch <br /> Divide the length(3)by perforation spacing(2)and round <br /> down to nearest whole number. <br /> 2.5 8 14 18 28 <br /> Perforation spacing= (o(,e ft+ _,S ft=ate_spaces 3.0 8 13 17 26 <br /> 5. Number of perforations is equal to one plus the number of 3.3 7 12 16 254.0 7 11 15 23 <br /> perforation spaces(4). Check figure E-4 to assure the number of <br /> perforations per lateral guarantees <10%discharge variation. 1 5.0 6 10 14 22 <br /> spaces+ 1 = 2.7--, perforations/lateral E-6: Perforation Discharge in gpm <br /> 6. A. Total number of perforations= perforations per lateral (5) perforation diameter <br /> times number of laterals (1) head Inches <br /> (feet) 3/16 7132 1/4 11 <br /> a�perfs/lat x _lat= �L_perforations 1.Oa 0.42 0.56 0.74 <br /> B. Calculate the square footage per perforation. 2.0b 0.59 0.80 1.04 <br /> Should be 6-10 sqft/perf. Does not apply to at-grades. <br /> Rock bed area = rock width (ft) x rock length(ft) 5.0 0.94 1.26 1.65 <br /> /ft x (ou ft= taus Sgft a Use 1.0 foot for single-family homes. <br /> Square foot per perforation=Rock bed area +number of perfs (6) b Use 2.0 feet for anythina else. <br /> La q U sgft+_21-perfs = '.Z sgft/perf M"IFOLO 10CATED AT END OF PRESSURE DISTRIBUTION SYSTEM <br /> 7. Determine required flow rate by multiplying the total number of <br /> perforations (6A) by flow per perforation(see figure E-6) <br /> perfs x g m/perfs= �� gpm <br /> 8. If laterals are connected to header pipe as shown on upper ' <br /> example,to select minimum required lateral diameter;enter <br /> figure E-4 with perforation spacing (2) and number of perforations <br /> per lateral(5) Select minimum diameter for <br /> urour OF rERroR.rro vlvE I..rER.Is FOR <br /> perforated lateral= inches. PRESSURE D STRIOUTION IN MWW <br /> KRNNYTSp <br /> R.STK PK <br /> 9. If perforated lateral system is attached to manifold pipe near CE,�„�,m "coo <br /> the center,lower diagram,perforated lateral length(3) and VIEW 7aN ,Ta+ <br /> truPxrcoo <br /> number of perforations per lateral (5)will be approximately one KIr�sI�aP ��orTw o, <br /> half of that in step 8. Using these values,select minimum �- <br /> diameter for perforated lateral = IL-1_inches. <br /> If <br /> too <br /> I hereby certify that I have completed this work in accordance with applicable ordinances, rules and laws. <br /> (signature) 3 c)L4 (license#) z--)g-b Z (date) <br />