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PUMP SELECTION PROCEDURE <br /> `11. Determine pump capacity: <br /> A. Gravity distribution <br /> 1. Minimum required discharge is 10 gpm <br /> 2. Maximum suggested discharge is 45 gpm. For other <br /> establishments at least 10%greater than the water supply rate, <br /> but no faster than the rate at which effluent will flow out of the <br /> distribution device. <br /> B. Pressure distribution <br /> See pressure distribution work sheet <br /> From A or it Selected pump capacity: 3 I - gpm <br /> 2. Determine_pump head requirements: <br /> A. Elevation difference between pump and point of discharge? soil treatment system <br /> l S feet &point of discharge <br /> tlieW /04,0 <br /> B. Special head requirement? (See Figure at right - Special Head Requirements) total pipe <br /> length <br /> S feet 77 2A.elevation <br /> inlet ;:_.,;:>::":''::'., <br /> C. Calculate Friction loss pipe difference <br /> 1. Select pipe diameter . in <br /> 2. Enter Figure E-9 with gpm (1A or B) and pipe diameter (Cl). ^^ <br /> Read friction loss in feet per 100 feet from Figure E-9 Special Head Requirements <br /> Friction Loss =_f•i.e, ft/100ft of pipe Gravity Distribution 0 ft <br /> 3. Determine total pipe length from pump discharge to soil treatment Pressure Distribution 5 ft <br /> discharge point. Estimate by adding 25 percent to pipe length for <br /> fitting loss. Total pipe length times 1.25 = equivalent pipe length <br /> F;9: Friction Loss in Plastic Pipe <br /> a30 feet x 1.25 = a''q feet <br /> Per 100 feet <br /> 4. CaIculate total friction loss by multiplying friction loss (C2) nominal <br /> in ft/100 ft by the equivalent pipe length (C3) and divide by 100. pipe diameter <br /> = ).(r, ft/100ft x '7,V q =100 = S ft flow rate 1.5" 2" 3" <br /> !p,tn <br /> D. Total head required is the sum of elevation difference (A), special 20 2.47 0.73 0.11 <br /> head requirements (B), and total friction loss (C4) 25 3.73 1.11 0.16 <br /> I S ft+_ S __ft+ ,g _ft = 30 5.23 1.55 _ 0.23 <br /> Total head: D.„( feet <br /> 35 6.96 2.06 0.30 <br /> 40 8.91 2.64 0.39 <br /> 3. JPuirap selection 45 11.07 3.28 0.48 <br /> - 50 13.46 3.99 0.58 <br /> 55 4.76 0.70 <br /> A pump must be selected to deliver at least- 3 1 _gpm 60 5.60 0.82 <br /> (1A or B) with at least 2.5 feet of total head (2D) 65 6.48 0.95 <br /> 70 7.44 1.09 <br /> I hereby certify that I have7c,ompleted this work in accordance with applicable ordinances, rules and laws. <br /> 1.-------- <br /> -- / , ^ <br /> ., (-- ` 1 � ;4',...-A/.---'----. <br /> _ ._._.-„".�'_,... (signature) 3'i Lt (license if) 4- ,,!'?-0 0 (date) <br />