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•V1\/vl\LJ aI LJI\-71.N V V1\1\J 11 L L l <br /> (For Flows up to 1200 gpd) <br /> . A. FLOW Estimated Sewage Flows'in Gallons per day <br /> Estimated Li S. gpd Number Type 1 Ty nType,Il Ix <br /> or measured x 1.5 = gpd. Ballroom <br /> t>s <br /> 1 <br /> B. SEPTIC TANK LIQUID VOLUMES 2 6'00 375 256 <br /> 3 450 3(X) 218 tosc <br /> 4 600 375 256 ordse <br /> vaities <br /> 7505 6 s50 332Z- 1000 f gallons iTe I. <br /> 7 1050 600 370 II,.. <br /> 8 1200 675 408 III <br /> C. SOILS (refer to site evaluation) "'"ns <br /> 1. Depth to restricting layer = inches feet Septic Mink Capacities(In gallons) <br /> 2. Depth of percolation tests = / .2- inches Number of Minimum Liquid Liquid capacity with <br /> Bedrooms Capacity garbage disposal <br /> 3. Texture k o cc.0-- Percolation rate -.Z mpi <br /> 2 or less 750 1125 <br /> 4. Land slope / A TO 3 or 4 1000 1500 <br /> 5 or 6 1500 2250 <br /> 7,8 or 9 2000 3000 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> 11-5-0 gpd x 0.83 sq. ft./gpd =5.g'0 sq. ft. <br /> 2. Select width of rock layer (max 10' if <120 mpi max 5') = / 0 ft. <br /> 3. Length of rock layer/= area j- width= :;,:-...7;a,, .rat..,-.r.e 1aPap�a. ah. .renav,'at <br /> 3 8Z) sq. ft. =r /0 ft. = 38' ft. lit.;P O P„.1 o a` a.nP7...-.L.--,,, <br /> � P..O.t7.1b.aD iD�rt�Ti.U.Yla vA:4`:c� Q..O`�n ii�L <br /> Width ft 2n(f 9' O� <br /> •M1 .�qw Q 't7 P -‘,...-.. ......0„:717.F.1 <br /> <120mpi <10' Length ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;SS"D sq. ft. x ) <br /> ft. = 30cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 3 87, cu. ft. -27= /Li cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; ) / cu. yd. x 1.4 <br /> ton/cu. yd. = .TO tons. <br /> F. ABSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is .5A mpi Percolation Rate in Gallons Rano of Absorption <br /> .Minutes per Inch Soil Texture per day per width to Rock ' <br /> Texture A noLM IMP!) square foot Layer width 1 <br /> Faster than 0.1 Coarse Sand 1.20 1.00 <br /> 0.1 to 5 Sand 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; 0.1 to 5 Fine Sand 0.60 2.00 <br /> CO6 to 15 Sandy Loam 0.79 1.52 <br /> D gp d/ft2 16 to 30 Loam 0.60 2.00 1 <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> 46 to 60 Clay Loain 0.45 2.67 <br /> • 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer Slower than 120 Clay 0.20 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; j <br /> 1.20 gpd/ft2+ . SD gpd/ft2 = / , y <br /> i <br /> 4. Multiply adsorption width ratio by rock layer width to get i <br /> required adsorption width; <br /> a?.el x 10 ft = Y ft <br />