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• t-19 <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW D-7 <br /> Estimated 60c) gpd (see pages D-7 or I-3,4, 5) howl IN Gu0.13 rot,.r <br /> KA ER IVP. Or,K110E4CE• <br /> Of <br /> or measured gpd. 0E000000S I n II s <br /> 7 100 721 140 $01t <br /> 3 450 300 21• •, <br /> 4 600 3T1 2510 •O1'• <br /> B. SEPTIC TANK LIQUID VOLUMES .'0 4n TT!' <br /> 2-/OOl7 gallons (see pages C-3 or C-5) 7 <br /> 1010 $73 7/O <br /> 1700 GOO .w Ca�.r <br /> BXGs3l,0,p7-.Ko n-1Ad:F v„C sty C,ly C-3 <br /> C. SOILS (refer to site evaluation) SEPTIC TANK CAPACITIES. IN GALLONS <br /> 1. Depth to restricting layer = Ce inches Yl/Y10/ 1R•WUY ` 0 C...�1r <br /> .100 .R$.CE <br /> 11640010111J01.00CAPACR, 00110101 <br /> 2. Depth of percolation tests = /Z- inches ,OR u,. ,EE „E, <br /> 3. Percolation rate mpi EOR• 101E 1E90 <br /> Q� E0RE ,EEE 3310 <br /> 4. Land slope ,- ' - /� T,.,0.1E „EE ,EE, <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> t c' 2 gpd x 0.83 sq. ft./gpd =S00 sq. ft. <br /> 2. Select width of rock layer (10 feet or less) = /0 ft. <br /> 3. Length of rock layer = area width = <br /> SOD sq. ft. + /0 ft. = S7, ft. Rock Bed <br /> f•f,r•f•f•�,f•f•f•f.f•f.j.f•f <br /> ti.ti.ti•ti•ti.'`.ti.L.1i.ti•ti.ti•`•L•t.. <br /> {f�fti��fvfL:�:�ftif�ftir{��ftif{f�Width 510 <br /> .555545_f5f5+5rtrrr•r;r r•r_r. <br /> E. ROCK VOLUME Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> Soo sq. ft. x / ft. =Soo cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. d to get cubic yards; <br /> SCO cu. ft. � 27 = /I..' cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> / ,S cu. yd. x 1.4 ton/cu. yd. = 20 tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is /7 mpi E-16 <br /> 2. Select allowable soil loading rate from table on page E-16; 111.0YYULO.UM IYRIEO.EOU 11.01/1 Y0U.Ef <br /> gpd/ft2 ......� ...........�. � <br /> R.•..1 M..1 w- <br /> 3. Calculate adsorption width ratio by dividing rock layer "'" N'•' '�" `"•• <br /> 0.1 , 1.00 3.0E 0.0$ 1.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate 11 •'E 1'E 11 '•E <br /> �1E 3•- E..E- E.EE t... E.EE <br /> 1.20 gpd/ft21 Go gpd/ft2 = Z'n� 31 .E 0.3E I II )E3 7... <br /> IE II E..1 0.10 1.0 LO <br /> E1 1 E.0 0.10 ..0 LE. <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> 10 x L ft = 20 ft <br />