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1993 - Septic System
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8/22/2023 4:37:19 PM
Creation date
1/23/2020 9:51:53 AM
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x Address Old
House Number
2110
Street Name
Webber Hills
Street Type
Road
Address
2110 Webber Hills Rd
Document Type
Septic
PIN
0311723340011
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' . MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day <br /> Estimated (.,,oo gpd (see pages D-7 or I-3,4, 5) Number (gam) <br /> or measured gpd x 1.5 = - BedType 1 Type II Type 11f Type <br /> V• <br /> B. SEPTIC TANK LIQUID VOLUMES 2 450 225 <br /> 3 450 300 21818 218 60R <br /> 4 600 375 256 a <br /> lues <br /> D., -) o 0 o gallons (see pages C-3 or C-5) 5 750 450 94 is <br /> 6 900 525 332 T1. <br /> 7 1050 600 370 m <br /> 8 1200 675 408 columns <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer = k a' 1 inches <br /> Septic Tank Capacities,in galkms <br /> Number of Minimum Liquid Liquid capacity with <br /> 2. Depth of percolation tests = a " inches Bedrooms •Capacity garbage disposal <br /> 3. Percolation rate I I. Co mpi 2 or less 750 1125 <br /> 3 or a 1000 1500 <br /> 4. Land slope - % 4 a 6 15003250 <br /> 7.8 or 9 ZpOp 3000 <br /> over 9 .._._ <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = l <br /> (oo gpd x 0.83 sq. ft./gpd = L c1 sq. ft-+ )0°70= s��II <br /> 2. Select width of rock layer (10 feet or less) = / o ft. <br /> 3. Length of rock layer = Area= Width = <br /> SLi 7 sq. ft. i I b ft. = SS ft. Rock Bed <br /> •'• tititi•ti••, t•ti•ti <br /> {fti:•ti.••J•t•f •f.•r.tif.tiftiftif.tif.; <br /> • dth <10 ft <br /> ,f,r.f .P•e.0.".0,r,r,f,f,f,f...P, - . <br /> E. ROCK VOLUME •f-j f r f'r=•'gth- - ---.-1---..-' ra <br /> �- Length f <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> 54-) sq. ft. x /.0s ft. = 5i Li cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 5'i y cu. ft. - 27= a I cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> a I cu. yd. x 1.4 ton/cu. yd. = a.c7 tons. <br /> F. ADSORPTION WIDTH c.'-A`-i 0l4 W-► <br /> 1. Percolation rate in top 12 inches of soil is H. (, mpi Absorption Width Sizing table <br /> Perco2. Select allowable soil loadingrate from table on page E-; in Minute Rate Gallons Ratio of <br /> p g in Minutes per Soil Texture per day per Absorption width <br /> Rock Layer <br /> Inch(MPI) square foot to <br /> 4 5' gpd/ft2width <br /> 3. Calculate adsorption width ratio by dividing rock layer Faster than 0.1• Coarse Sand ..___ <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; .l t Fine Sed" .60 1.00 <br /> o.l to 5•• 0.60 2.00 <br /> 1.20 gpd/ft2j- .1.-),( gpd/ft2= a - L 0 . 6 3 Sandy Loam 0.79 21.00 <br /> I6 to 30 Loam 0.60 2.00 <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> Check this value on page E-16. 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 4. Multiply adsorption width ratio by rock layer width to get Slois27.than Clay <br /> required adsorption width; <br /> a.Gr) x ) o ft = ai,.' ft <br /> I <br />
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