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2095 Webber Hills Road - 03-117-23-34-0023
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Last modified
8/22/2023 4:37:49 PM
Creation date
1/22/2020 2:29:07 PM
Metadata
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x Address Old
House Number
2095
Street Name
Webber Hills
Street Type
Road
Address
2095 Webber Hills Rd
Document Type
Septic
PIN
0311723340023
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• MOUND DESIGN WOltKtinliiLr <br /> ' (For Flows up to 1200 gpd) <br /> A. FLOW .,...,.�.,....__....�.,. ............__� <br /> 1rttimatul ocwog,,I er••s.it,CrCuii pa 1. <br /> (82)4) <br /> Estimated0 v gpd (see pages D-7 or I-3, 4,5) �anr; ��.- - --- <br /> or measured ----- gpd x 1.5 = -----_. nr 1)Tc 1I 1 II'nPe_ ,`T <br /> Iledra,,,. 1____._.. . <br /> 2 300 275 180 <br /> B. SEPTIC TANK LIQUID VOLUMES 3 450 300 218 <br /> 4 600 375 256 "1`ti' <br /> r,wta <br /> -/0 0 0 gallons (see pages C-3 or C-5) 5 7511 450 294 la <br /> pages 6 900 525 332 _1• <br /> 7 100 600 370 of <br /> (! 1200 675 408 tri•.n•t <br /> C. SOILS (refer to site evaluation) _ ._.,.__...._ <br /> II $.yak ia.rt Capra ilia,kr gado t <br /> 1. Depth to restricting layer= 1 4( To cif inches <br /> N+un'w at Mina'Minirnum Llgvid�IJ•luid cap.dI *liltr <br /> 2. Depth of percolation tests = ) a inches Walt coma Capacity 'artist dIcria.I <br /> 3. Percolation rate < p -11 t+c�. I.1.ra11110 2ceIca, 7;11 lin <br /> �. �' mpi clzt1-.14l us .1,011_,- 3cr4 um Iwo <br /> 4. Land slope 4 % 74ar ol°o ic?o <br /> ever 9 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = <br /> C '0 o gpd x 0.83 sq. ft./gpd = 4Pr c< sq. f t.-'r 00= 5'4117 <br /> 2. Select width of rock layer (10 feet or less) = /u ft. <br /> 3. Length of rock layer T Area+Width = <br /> S-1'7 sq. ft. + /0 ft. = .S ft. Rock Bed <br /> r r• ! r•r .•r•!•.'•J•J <br /> •.r••r•r r•!.r•r •r•rr•r•! <br /> •r; sit) <br /> /-s' <br /> !_!_rJ r lJ_J_r:r_t_J_r_J_�� <br /> E. ROCK VOLUME F-- Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> Su 7 sq. ft. x/c), .ft. = 5' cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> .5r/2. cu. ft. +27 = D\I cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> a) cu. yd. x 1.4 ton/cu. yd. = a`7 tons. <br /> F. ADSORPTION WIDTH e.l-4LC v1') <br /> 1. Percolation rate in top 12 inches of soil is .co mpi Absorption Width Sizing Table' . <br /> Percolation Rete Gallons Ralio or <br /> 2. Select allowable soil loading rate from table on page E-; <br /> InrMneMePer So11batum per adrayror AoKRwpowyd <br /> .1- gpd/ft2 Wid <br /> th <br /> . <br /> 3. Calculate adsorption width ratio by dividing rock layer Neter t ano 5.1• Coarse <br /> o's Sand .-0. 1:00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; °. 5ts a 0.60 2.006 oMg <br /> 1.20gpd/ft2+ ,L1 gpd/ft2= a.I., 16to30 Loam 0.60 2.00 <br /> 31 to 45 Slit loam 9.50 2.40 <br /> Check this value one a E-16. 46 to _ <br /> _60_ __Clay Loan (0.45) 2.67 <br /> P 8 `ab a 120 Clay 0:24 5.00 <br /> 4. Multiply adsorption width ratio by rock layer width to get SI ;fan Clay - -- <br /> required adsorption width; <br /> a.L-,') x 10 ft =)r,.7 ft <br /> / <br />
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