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1992 - Septic System Info
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1992 - Septic System Info
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Last modified
8/22/2023 4:37:37 PM
Creation date
1/22/2020 10:18:54 AM
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x Address Old
House Number
2040
Street Name
Webber Hills
Street Type
Road
Address
2040 Webber Hills Rd
Document Type
Septic
PIN
0311723340016
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. • . MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW 1stimatcd Sewage Flows in Gallons pa day <br /> Estimated c-?, () gpd (see pages D-7 or I-3,4, 5) ' Number ( � <br /> c-?, () <br /> or measured ---- gpd x 1.5 = ---- • Tied on,a ape I '�'Pe II 'Pipe III Type <br /> 2 300 225 IRO N <br /> B. SEPTIC TANK LIQUID VOLUMES 3 Oso 300 218 6D" <br /> 4 600 375 256 fa <br /> -1 ','--.' 1- t oc c gallons (see pages C-3 or C-5) <br /> S 750 450 294 i■ <br /> 6 900 525 332 �•t . <br /> 7 1050 600 370 0 <br /> 8 1200 675 408 means <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer= ;23, -co ' <br /> ,i inches Sciatic Tisk c.oackla■In tonnes <br /> Number or Minimum Liquid Liquid rapacity with <br /> 2. Depth of percolation tests = 1a, inches Bedroom§ C,paclty gerbille disposal <br /> 3. Percolation rate . 1 mpi -\...;\L-1 L ,, „1 23or u 4 750 <br /> , <br /> 1125 <br /> 4. Land slope r! % 34.6 91500 4150 <br /> over 9 •.-•. <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = <br /> `tic gpd x 0.83 sq. ft./gpd = (,-,) sq. ft. .* log=e _ G.v,t-1 <br /> 2. Select width of rock layer (10 feet or less) _ / 6 ft. <br /> 3. Length of rock layer = Area+ Width = <br /> !.--,'Li sq. ft. + / ,_ ft. = (.--✓, ft. Rock Bed <br /> :•1.1.1•x•1.1.1.1.1.1•r•r•1•. .. <br /> • <br /> ;s::::fti:;A.:;rLftftiftiftifti::::;:'Width S1O ft. <br /> •1•r•r•r•r•r•r•1 ••r•r•t 1•r•r•r; �-, <br /> 1•ti741.r r•'L•tie\•t•"•ti••.•ti•Mr.7% <br /> E. ROCK VOLUME I Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> c--,1 sq. ft. x /.:),-; ft. = 9 cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> ')l v cu. ft. + 27 = i cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> .-1,`) cu. yd. x 1.4 ton/cu. yd. = 27: tons. . <br /> F. ADSORPTION WIDTH .-`-}',--( k_._o 1 `1 1 <br /> Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is 3. 1 mpi <br /> Percolation Rate Gallons Ratio of <br /> 2. Select allowable soil loading rate from table on page E-; <br /> InIMcihnu(MsPpa Soil Mature pur adreey fol Athos Rpllon wyierdt <br /> Ft <br /> . L_j _- gpd/f Width <br /> 3. Calculate adsorption width ratio by dividing rock layer Palter than 0.1• Coarse Sand .-_- -- <br /> 0.1 <br /> ._ <br /> 00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; o.i to5•• FineS.annd•• 1.20nd 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 1.20 gpd/f t2+ . t-.l gpd/f t2= - („/") . 16 to 30 Loam 0.60 2.110 <br /> 31 to 45 Sllt Loam 0.50 2.40 <br /> Check this value on page E-16. 46to60 Clay loam 0.45 2.67 <br /> 60 to 120 Clay 0.245.00 <br /> 4. Multiply adsorption width ratio by rock layer width to get Sloan Clay ._.. _.. <br /> required adsorption width; <br /> a.r,.--) x I_-) ft = :) r..') ft <br /> 1 <br />
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