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1993 - Septic System info
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1993 - Septic System info
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Last modified
8/22/2023 4:37:38 PM
Creation date
1/22/2020 9:27:58 AM
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x Address Old
House Number
2000
Street Name
Webber Hills
Street Type
Road
Address
2000 Webber Hills Rd
Document Type
Septic
PIN
0311723340017
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. . . MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day I <br /> (Bpd) <br /> Estimated 2p0 gpd (see pages D-7 or I-3, 4, 5) Number <br /> of Type I Type II Type III Type <br /> or measured gpd x 1.5 = Bedrooms IV <br /> 2 300 225 180 <br /> B. SEPTIC TANK LIQUID VOLUMES 3 450 300 218 <br /> 4 600 375 256 o(th <br /> gallons (see pages C-3 or C-5) 5 750 450 294 is <br /> P g 6 900 525 332 �y,e 1. <br /> 7 1050 600 370 1 <br /> 8 1200 675 408 cameos <br /> C. SOILS (refer to site evaluation) - <br /> 1. Depth to restricting layer = 1 -1 <br /> inches Septic Tank Capacities,in gallons <br /> 2. Depth of percolation tests = 12 <br /> I^ inches Number of Minimum Liquid Liquid capacity with <br /> Capacity garbage disposal <br /> 3. Percolation rate Al mpi 2orkss 750 1123 <br /> 3 or 4 1000 1523 <br /> 4. Land slope e---s., 4 or 6 1500 <br /> 7.8 or 9 2000 2203000 <br /> over 9 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x - (�O(s) = <br /> C gpd x 0.83 sq. ft./gpd = .1--%(-D sq. ft. <br /> 2. Select width of rock layer (10 feet or less) = )0 ft. <br /> 3. Length of rock layer = Area _Width = <br /> 90 sq. ft. _ l'O ft. = SO ft. Rock Bed <br /> r.:.r:,r.f:�:�;:•t+:•lel.'•1�l•l I <br /> • l 1l t•: •1 f lel.• •f`: <br /> :ti ti { ti ti .ti ti ti `1, idth 510 ft. <br /> •ff•ft-•~• ff• •f• f•f ff 1 <br /> E. ROCK VOLUME )!--- Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> sq. ft. x 1 ft. =i cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd.to get cubic yards; <br /> Soo cu. ft. + 27= 19 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 1C? cu. yd. x 1.4 ton/cu. yd. = 2-1 tons. <br /> F. ADSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is mpi Percolation Rate Gallons Ratio of <br /> 2. Select allowable soil loading rate from table on page E-; in Minutes per Soil Texture per day per Absorption width <br /> t7.' l gpd/f t2 - _ Inch(MP1) square foot to Rock Layer <br /> Width <br /> 3. Calculate adsorption width ratio by dividing rock layer Faster than 0.1• Coarse Sand ----- --- <br /> 0.1 to 5 Sand 1.20 1.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 0. o5ss S 0.60 2.006 1a � 0.79 <br /> 1.20 gpd/ft2+ 050 gpd/ft2= Z Z . arc) 131to45 Silt to 30 Loam 0_5600 22,'400. <br /> Check this value ona e E-16. 46 to 60 clay Loam 0.45 2.67 <br /> P g• 60 to 120 Clay 0.24 5.00 <br /> 4. Multiply adsorption width ratio by rock layer width to get Sloesthan Clay - • - <br /> required adsorption width; <br /> 2r4to x to ft =ZZ-i- ft , <br /> 1 <br />
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