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1993 - Septic System approval
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160 Wear Lane North - 33-118-23-34-0014
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1993 - Septic System approval
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Last modified
8/22/2023 4:50:56 PM
Creation date
1/21/2020 2:37:24 PM
Metadata
Fields
Template:
x Address Old
House Number
160
Street Name
Wear
Street Type
Lane
Street Direction
North
Address
160 Wear Lane North
Document Type
Septic
PIN
3311823340014
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ProcessedPID
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• <br /> ENO PEAFORATICN OF A PEAFOPATED <br /> PRESSURE Q(STRIBUTION SYSTEM <br /> Gra.. Caere <br /> 1 l <br /> 1. Select number of perforated laterals --3 Taowux <br /> -• • Laker of G.stenll. Fabric (or(cur <br /> Lawny Sana Layer : Ince later el hay or aro"covered <br /> 2. Select perforation spacing = -_-3 feet. ;�, ` . ^"�'°"^ <br /> f i1 1- Peftaratloa OrIll.d Neruonlally <br /> Ints Cap Neel 1. <br /> 3. Since perforations should not beplaced closer than 1 ft. to .Ptu. T ClLeer Iz•I. Edge <br /> ikOrai^ FleI P.c►zr. {!'1y of Real Layr <br /> the edge of the rock layer (see diagram), subtract 2 ft. from P•rfa.atlan..ucat.d of <br /> the rock layer length. clan Sand L. eattem of Lateral <br /> 6v�J �///_7( /Origin Sall Praa.rfy Scarl Mod' <br /> 2 ft. -- `_-"_'_ feet. Wart Plaang Sand Layer <br /> Rock layer length TABLE OF PERFORATION DISCHARGES IN GPM <br /> f <br /> 4. Determine the number of spaces between perforations. Head Perforation diameter(inches) <br /> Divide the length above by perk.- :).pscing and round 1ri ,i <br /> down to nearest whole number. <br /> ' n <br /> V „ j �� / 0s6 ��(---...____3.14:----) ; <br /> 1.5 0.69 0.90 <br /> Length perf. spacing .66 ft. +3 ft. = Q a- spaces ub 00.80.89 1.04 <br /> 17 <br /> (3) (2) 3.0 0.98 123 <br /> 5. Number of perforations is equal to one plus the number of 4.0 1.13 1.47 <br /> 5.0 1.26 1.63 <br /> perforation spaces . <br /> f ...Use 1.0 foot of head for residential systems. <br /> !1 bUse Z0 feet of head for other establishm.-, <br /> �07 spaces + 1 = J-3 perforationsilateral <br /> 6. Multiply perforations per lateral by number of laterals to11.25 inch.5 inch 1.1..iinu <br /> Irrl ch 2.0 tech <br /> get total number of perforations. 2S 14 18 2s <br /> / 3.0 13 17 26 <br /> v _ _ (p7 3.3 12 16 23 <br /> X perforations. 4.0 11 15 23 <br /> laterals perfs/lateral- p 5.0 10 14 22 <br /> 7. Determine required flow rate by multiplying <br /> number of perforations by flow per perforation <br /> 9 6,7 JF x3 V -_�V gpm. � 0,0Ml <br /> ..,,, LOCOED .T or 27JK QSTTRR1 <br /> , aw STSTSY <br /> 8. If laterals are connected to header pipe as shown on upper <br /> example, to select minimum required lateral diameter; enter -�"j•• <br /> table with perforation spacing and number of perforations y,,� <br /> per lateral. Select minimum diameter for \,,---- <br /> perforated lateral = inches. <br /> WWI Or..rr.n..rrr...r LAM..l en <br /> n ..•r carte r: _y.p'.t <br /> 9. If perforated lateral system is attached to manifold pipe near ' �` ,� <br /> the center, lower diagram, perforated lateral length and • -;.:r. -_. <br /> ,. L <br /> number of perforations per lateral will be approximately one -����:� <br /> half of that in step 8. Using these values, select minimum ..- '" ---"`, ,.•-�\ <br /> diameter for perforated lateral = ./ inches. \,----,.- <br /> ' <br /> • <br />
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