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MOUND DESIGN WORKSHEET
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<br /> (For Flows up to 1200 gpd)
<br /> A. FLOW Estimated Sewage Flows In Gallons per day
<br /> Estimated `)So gpd (,c,00 ,))-p-a4 x.�,AL>) Then 7y7em e
<br /> or measured - x 1.5 = - gpd.
<br /> 2 300 225 Iso nos
<br /> 3450 300 218 arseB. SEPTIC TANK LIQUID VOLUMES 4 600 375 256 ,relies
<br /> 5 750 450 294 4,
<br /> .3, U gallons ?'••\• -c-)>1,\-- < ,-)0 0 0< ,,-,\ 1-10,30- ,,,,-,-s- T4 N Y-- 6 900 525 332 Type L
<br /> C,o>+v¢.T-f 7 y nv\'-ta f�\4 -fo '-i=t,'?-I'll- 1-4}04- ) I 7 1050 600 370 n«
<br /> 8 1200 675 408 m
<br /> 1�1S tA�� 11 V 1 a So ^\. FC-1,,,,,v7, sA}lL i I (column
<br /> C. SOILS (refer to site evaluation) S.vdeTT.ICac.d11 i.cwo.1/
<br /> 1. Depth to restricting layer=)a,,1y,l inches - feet *tabor of Midas=Liquid Liquid wacky who with disposal
<br /> 2. Depth of percolation tests = d ,V 1›.140_ veers GP7 preset dapaal Iln laddr
<br /> a I) inches so 1
<br /> 2
<br /> - O
<br /> 125 15C0
<br /> 3. Texture L\--1- -
<br /> A�( L c�-,-, Percolation rate S. i mpi 3 4 I so 1Xto
<br /> 5 M a15c0 (2250Th �000
<br /> 4. Land slope '-1 % 7,1.KY... -7000----- -"saoo
<br /> D. ROCK LAYER DIMENSIONS
<br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 �,
<br /> 0v gpd x0.83 sq. ft./gpd = c,-;, , sq. ft.1 � c
<br /> -)� . y° Cssofxl,,,ue�
<br /> 2. Select width of rock layer (max 10' if <120 mpi max 5') = 10 ft.
<br /> 3. Length of rock layer = area + width = "• ....- .....- .•• . �s-�.ar,�,�o,�,.•,^.._.-
<br /> (. u -) sq. ft. + _L4._-ft. = ,� ft. )o . pQ '_ A
<br /> Q. i(�':a-.r.-..�r"_a-lc•.(1.,r..4`.<II'i-pus-..'j.A
<br /> `�
<br /> 4, -,- - 1 - 1 Width io ft w► 0. P. 0! .i i�w�� . +ef li
<br /> �j 0.3oo✓Sa, ,_) <120mpi <10' Length cace ft s ,4,.=-A),
<br /> >120mpi <5' >.4•77:D - 1 3
<br /> E. ROCK VOLUME
<br /> 1. Multiply rock area by rock depth to get cubic feet of rock; ):m sq. ft. x Lo.c
<br /> ft. = 13 le Cu. ft.
<br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards;
<br /> J.3 ,2 cu. ft. +27 = cu. yd.
<br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; cu. yd. x 1.4
<br /> ton/cu. yd. = I) tons.
<br /> F. ABSORPTION WIDTH Absorption Width Suing Table
<br /> 1. Percolation rate in top 12 inches of soil is S- ) mpi Percolation Plea in Gallons Rano ofAbsor
<br /> Mau per loch Soil Tenure per der per width to Ro
<br /> Texture L'-p U o 1,"-1cr,Pu ,gtnre roe Dyer Vlld
<br /> Facer than 0.1 Coarse Sand 1.20 1.00
<br /> 0.1 to S Sand 1.20 1.00
<br /> 2. Select allowable soil loading rate from table; 0.1 m 5 Flan sand 0.60 zoo
<br /> p 6 to 15 Suety Loam 0.79 1.52
<br /> �- gpd/ft2
<br /> 16 s0 30 Loom 0.60 2.00
<br /> 3I45 lay Loanst Loam 0.45 2.46 so 60 2.4
<br /> - 60 so 120 Clay 0.24 5.00
<br /> 3. Calculate adsorption width ratio by dividing rock layer lc"'"' ae 120 aa>' 0.20 6.03
<br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate;
<br /> 1.20 gpd/ft2+.‘-) s- gpd/ft2= . -L-') .
<br /> 4. . Multiply adsorption width ratio by rock layer width to get
<br /> required adsorption width;
<br /> ..l,/-) x Jo ft = ,)c..'7 ft
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