Laserfiche WebLink
` MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW EstlrnMed Sewage Flow In Gallons pa Day(gpd) <br /> Estimated `-1,0 gpd Number <br /> ° Type I Type 11 Type III Type ry <br /> or measured - x 1.5 = - gpd. Bedrooms <br /> 2 300 22.5 180 ro. <br /> 3 450 300 218 •1 <br /> B. SEPTIC TANK LIQUID VOLUMES 4 600 375 256 <br /> 5 750 450 294 <br /> -JO 0 0 gallons 6 900 525 332 'k <br /> 7 1050 600 370 ,dm. <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) M•+ I ►I-- <br /> 1. Depth to restricting layer= oro ,a,a ico 3o Inches 8 c„r,, ,,,�,, <br /> 2. Depth of percolation tests = ► 'S inches <br /> 3. Percolation rate y• t., mpi 2 or ka4 7S0 ' "5 <br /> 3 or 4 1,000 1,500 <br /> 4. Land slope V % ser 6 1,5013 2.250 <br /> 7 a E 2,000 3.000 <br /> over 9 Sim fig.C-6 (r IS) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = ' <br /> tiS0 . gpd x 0.83 sq. ft./gpd = 3�3,sq. ft:-}) `\10a <br /> 2. Select width of rock layer (10 feet or less) = /D ft. <br /> 3. Length of rock layer = area+width = Rock Bed <br /> o sq. ft. + /0 ft. = 1--1 / ft. 77:3:747.355.7575733577*. <br /> •,•,•�. <br /> y ;.r•r <br /> �•r•r•r•r•r•r �•�? .r�r.r•r•r•iyyidth 510 ft. <br /> ;•r•r•r•S•{r r; Rr•r•r•r•� <br /> P•,.,•�.,,•wt •{{sus, 1 <br /> r r•r:r.r.r•�rsr_•�r.�r.r•�•r�1 <br /> E. ROCK VOLUME I Length --I <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> H i 0 sq. ft. x/.os' ft. = 430 cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft:/cu. yd. to get cubic yards; <br /> 430 cu. ft. +27= /J0 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> /i cu. yd. x 1.4 ton/cu. yd. = a k tons. <br /> F. ADSORPTION WIDTH z_k...+ 04-01 <br /> Absorption wlel h S1zL,�Lbk <br /> 1• Percolation rate in top 12 inches of soil is '-).Je mpi Percolation Rare can... tor r <br /> Minutes per incl, Soil Texture ,•r ''. <br /> „ <br /> I.. .:•E., <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse Sand 1.20 1.00 <br /> •4 S gpd/ft2 0.1 to 5 Sand 1.20 1.00 <br /> 0.1 to 5 Fine Sand" 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 3. Calculate adsorption width ratio bydividingrock layer 16 to 30 Loam 0.60 2.00 <br /> rP Y 31 to 45 Silt Loam 050 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 ClayLoam0.45 2.67 <br /> 61 3.00 <br /> 1.20 gpd/ft2+ rt--).Sgpd/ft2 = .1,V)) . Slower than 120 O 120 lay - - <br /> •'Soil hav4n6 50%a more at fax or very fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> D•L? x /0 ft= )-(0.9 ft <br />