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PRESSURE DISTRIBUTION SYSTEM - Trenches <br /> r c,..,t,,.ttl-t.,.,n,- <br /> 1 ta1UAHn`trvja fN'IMg1tCM!atMitllM./+6_7' 12 1. <br /> All boxed rectangles must be entered.the rest will be calculated. ,, t f.ti,,k i <br /> 1 <br /> re-rr F:ninpt:10".i'•-1 J d'• <br /> Vern , <br /> wt+acng IN-.,4' <br /> 1. Select number of perforated laterals: 3 <br /> 2. Select perforation spacing= 3 ft E4:Moltirxmallowable mentor orl/44richouttan on. <br /> per Mord b doers lue cion dictum vaiailon <br /> 3. Since perforations should not be placed closer that 1 foot to <br /> the edge of the rock layer(see diagram), subtract 2 feet from cared 1 itch I 1.2bInch 1.Ifrith 2A1nch , <br /> the rock layer length 23 a 14 18 2e <br /> 62.5 -2 ft= 60.5 ft 3.0 a 13 17 26 <br /> rock layer length 3-3 7 12 16 25 <br /> t.0 7 11 18 23 <br /> 3.0 6 10 14 22 1 <br /> 4 Determine the number of spaces between perforations. <br /> Divide the length (3) by perforation spacing(2)and round down to nearest whole number. <br /> Perforation spacing = 60,5 ft/ 3 ft= 20 spaces <br /> 5. Number of perforations is equal to one plus the number of perforation spaces(4). <br /> *Check figure E-4 to assure the number of perforations per lateral guarantees <br /> < 10%discharge variation. <br /> 20 spaces+ 1 = 21 perforations/lateral <br /> 6. A. Total number of perforations=perforations per lateral(5)times number of laterals(1). <br /> 21 perfs/lat x 3 laterals= 63 perforations <br /> E-6: PerfaraIvn C ischape In gpm <br /> B. Calculate the square footage per perforation. <br /> Should be 6-10 sgft/perf. Does not apply to at-grades. perforation diameter <br /> brad (inches) <br /> 1. Rock bed area=rock width(ft)x rock length (ft) (feet) 1/8 3/16 7/32 1/4 <br /> 10 ft x 62.5 ft= 625 ft2 1.Oa 0.18 0.42 0.56 0.74 <br /> 2. Square foot per perforation=Rock Bed Area/number of perfs(6) <br /> 625.0 ft2 / 63 perfs = 9.9 ft2/perf 2.0b 0.26 0.59 0.80 1.04 <br /> 5.0 0.41 0.94 1.26 1.65 <br /> 7. Determine required flow rate by multiplying the total number O u.�1.0 rcf,t t.or yrx7tc?..t.:R-rity N.:a-.4 <br /> of perforations(6A)by flow per perforations(see figure E-6) k,u i.o reel rut urxtrirKi etw. <br /> 63 perfs x 1 0.56 Igpm/perfs= 35.3 gpm <br /> 8. If laterals are connected to header pipe as shown <br /> ;,, tt,._ <br /> in Figure E-1, to select minimum required lateral '�1-• " <br /> diameter; enter figure E-4 with perforation spacing(2)and ; '� ' r -,,,,,v; I <br /> number of perforations per lateral (5). `' � ! <br /> Pietas I-1t Manifold Looafod al Ind of iydarn I <br /> Select minimum diameter for perforated laterals= inches <br /> 9, If perforated lateral system is attached to manifold pipe !T MatMleldteoaipod <br /> near the center, like Figure E-2, perforated lateral length (3) "1n�'ne'ca+ror«m..n+«� -' , <br /> and number of perforations per lateral(5)will be approximately <br /> one half of that in step 8. Using these values, select r- <br /> minimum diameter for perforated lateral= 1.5 inches. 1.�:_M <br /> I het-by certify the I have completed this work in accordance with all applicable ordinances, rules and laws. <br /> % (signature) 399 (license#) 8/6/2007 <br />