2008 - Soil & Percolation Testing

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Pressure Distribution Design Worksheet *` 1. Select Number of Perforated Laterals: 3 E-1 Geotextile ..."V7 0 v v �: Minimum( I 6 2. Select Perforation Spacing: 3.0 ft t,1a 'I. perforations spaced 3'apart'..4.1 7-• 2'of rock -, --,.....,& Perforation Diameter 1/4 inch �� 3. Select Pe rf . jy` l1aTr iuT ,ia �l)a rt)_ �Z 4 Length of Laterals=Media Bed Length-2 Feet r� � z ? r Tr t+. Tr > 50 - 2ft = 48 ft Perforation sizing:'A'to'A' Perforation spacing:2'to 3' 5. Determine the Number of Perforation Spaces. Divide the Length of Laterals(Line 4)by the Perforation Spacing(Line 2)and round down to the nearest whole number. Number of Perforation Spaces= 48 ft = 3 ft = 16 Spaces 6. Number of Perforations per Lateral is equal to 1.0 plus the Number of Perforation Spaces(Line 5). Perforations Per Lateral= 16 Spaces t 1 = 17 Check Table I to ensure that the number of perforations per lateral guarantees less than a 10%discharge variation. Table t Maximum Number of Perforations Per Lateral to Guarantee-'10%Discharge Variation '/r Inch Holes 3/,y Inch Holes 14 Inch Holes Perforation Pipe Diameter(Inches) Perforation Pipe Diameter(Inches) Perforation Pipe Diameter(Inches) Spacing(Feet) 1 115 115 2 3 Spacing(Feet) 1 11/4 11/2 2 3 Spacing(Feet) 1 114 11/2 2 3 2 10 13 18 30 60 2 12 18 26 46 87 2 21 33 44 74 149 215 8 12 16 28 54 2/ 12 17 24 40 80 214 20 30 41 69 135 3 8 12 16 25 52 3 12 16 22 37 75 3 20 29 38 64 128 7. Total Number of Perforations equals the Number of Perforations per Lateral(Line 6)multiplied by the Number of.Perforated Laterals(Line 1). 17 Perforations Per Lateral X 3 Number of Perforated Laterals = 51 Total Number of Perforations Calculate the Square Feet per Perforation Table II Table Ill Recommended value is 6-10 ft'per perforation. Does not apply to At-Grades Volume of Liquid in Pipe Perforation Discharge(GPM) 8- Bed Area = Bed Width(ft)X Bed Length(ft) Head Perforation Diameter Pipe Diameter Liquid Per Foot (ft) ft 1 , > t 50 'ft X 10 tt = 500 I ft' (inches) (Gallons) ) /e /id /tz /4 9. Square Foot per Perforation=Bed Area(Line 8)divided by the Total Number of Perforations(Line 7). 1 0.045 1'� 0.18 0.41 0.56 0.74 500 ft' 51 perforations = 9.80 ftz/perforations 1.25 0.078 2-0c 0.26 0.59 0.80 1.04 1.5 0.110 5.0` 0.41 0.93 1.26 1.65 10. Select Minimum Average Head: 1.0 ft 2 0-170 a:Use 1.0 for dwellings using 1/4 inch or 3 0.380 3/16 inch holes. 11. Select Perforation Discharge(GPM)based on Table Ill: 0.74 GPM per Perforation 4 0.661 b:Use 2.0 for dwellings using 1/8 inch holes;or,for other establishments using 12. Determine required Flow Rate by multiplying the Total Number of Perforations(Line 7)by the 1/4 inch or 3/16 inch holes. Perforation Discharge(Line 11). c:Use 5.0 for other establishments using 51 Perforations X 0.74 GPM per Perforation= 38 GPM 1/8 inch perforations. 13. Select Type of Manifold Connection(End or Center): End manifold pipe 1 r 14. Select Minimum Diameter of laterals based on Table I: 2.00 in � pipe from pump Determine Volume of Distribution Piping 15. Pipe Diameter of Distribution Pipe 2.00 dean outs ., ' 16. Volume of Liquid Per Foot of Distribution Piping: ! 0.170 'Gallons j _ alternate location i•� of pipe from pump 17. Length of Laterals=[Number of Perforations per Lateral-1]X Perforation Spacing ,_aeanouts - --- r 1 1 i X 3.0 ft = 45 ft J Manifold pipes 1 18. Volume of Distribution Piping= �f J _[Number of Perforated Laterals(Line 1)X Length of Laterals(Line 17)X ' _ p (Volume of Liquid Per Foot of Distribution Piping(Line 16)] `- � ` � Alternate location 3 X 45 X 0.170 = 22.95 Gallons '‘ ol pipe from pump 'rr Pipe from pump I hereby certify that I have completed this work in accordance with all applicable ordinances,rules and laws- Joseph J Olson � 810 11/242008 (Designer) (Signatum) (License#) (Date)