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• <br /> • PUMP SELEOTIONI'ROCEDURIK - <br /> --, A. Determine pump capacity: <br /> Gravity Distribution END PERFORATION OF A PERrONATED LATERAL <br /> 1. Minimum suggested is 600 gallons per hour(10 gpm) to stay ahead of .......-WOO CAW <br /> water use rate. <br /> r.,57.1/4 <br /> 4'" �,c} c"�` <br /> ' try' TopseN ) •� .: <br /> 2. Maximum suggested for delivery to a drop box of a home system is .,700 «•� <br /> Lorca of Goo4:1;11.17 Fabric ter lou• <br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. Loamy Send Lays 11inrn Inver suety eeeel.d <br /> • `T...,n're rosin paper) <br /> Pressure Distribution r,p.,ai r e Towing.CO,IIled Morleenlon, <br /> i.r•-.f:.,,�:, I:•. ,.1.210 Cep Now Top <br /> 3. a. Select number of perforated laterals 3 .,..,,4-Plus �,:,'-AI Leaar Ix•le cda. <br /> 1+ p fi.id_Posh, of Poch Lein <br /> b. Select perforation spacing= 3 ft. Per N1010111 Lecaled el <br /> c. Subtract 2 ft. from the rock layer length. Clan Sand Law, Gallons N Leurol <br /> t'Gy.;Gnslh-2 ft.= to co ft. T • ,r <br /> -'`Orielnel Soil Propnly Snaffled <br /> B.lor.Placing Sand Layer <br /> d. Determine the number of spaces between perforations. <br /> Length pert.spacing= 4 fo-ft.+ "z ft.= l spaces <br /> TABLE Of PORroiznriON DISCHARGES iN GPM <br /> e. D spaces+ 1 = A 3'perforations/lateral <br /> ' 1. Multiply perforations per lateral by number of laterals to Head Perforation diameic:Cinches) <br /> get total number of perforations. <br /> n <br /> � q i , r/3r 1/, <br /> Ina x penen.!ialrr.l= 4 /' perforations. 1))?�1. T 1 yl , <br /> 1.O3 0.56 0.74 <br /> g. tG».iie x AP.' v= '' i o r- • 2.013 0.x0 1.0044 <br /> • 23 0.89 i 1.17 <br /> 3.0 0.98 i 1.28 <br /> SELECTED PUMP CAPACITY 3 7 gpm 1,131.47 <br /> 5.0 1.2o I 1.65 <br /> B.Determine head requirements: <br /> aUse 1.0 foot of head for residential systems. <br /> 1. Elevation difference between pump and point of discharge. bUsc 2.0 feet of head for other establishments ( <br /> (_ feet <br /> 2. if pumping to a pressure distribution system,add five feet for pressure <br /> required at manifold <br /> .c feet <br /> 3. Friction loss Pipe Length <br /> a. Enter friction loss table with gpm and pipe diameter. I Point of Di charge <br /> Read friction loss in feet per 100 feet from table. I/0 7 <br /> F.L.= .t.y ft./100 ft of pipe Elevation Difference <br /> b. Determine total pipe length from pump to discharge Pump $1 <br /> point. Add 25 percent to pipe length for fitting <br /> loss,or use a fitting loss chart. Equivalent pipe F-18b <br /> length-1.25 times pipe length= <br /> 1.5 inch 2.0 inch 3.0 inch <br /> ce O x 1.25= 3 O feetgpm Friction tags per 100 ft of pip <br /> c. Calculate total friction loss by multiplying 10 0.69 0.20 <br /> friction loss in ft/100 ft by equivalent pipe length. 12 0.96 0.28 <br /> Total friction loss= ?SO x D.4,L) +100= '7 feet i 1.28 0.38 <br /> 4. Total head required is the sum of elevation difference, 16 1.63 0.48 <br /> special1headrequirements,and total friction loss. 20 2.03 0.60 <br /> 20 2.47 0.73 0.11 <br /> 25 3.73 1.11 0.16 <br /> / (r + + ? 30 5.23 1.55 0.23 <br /> 35 7.90 2.u6 0.30 <br /> (1) (2) (3c) • 40 11.07 2.64 0.39 <br /> 45 14.73 3.28 0.48 <br /> TOTAL HEAD 3 0 feet 50 3.99 0.58 <br /> 55 4.76 0.70 <br /> 60 5.60 0.82 <br /> Pump selection - -1. A pump must be selected to deliver at least } gpm (Step A) <br /> with at least 30 feet of total head (Step fi). . <br />