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1999 - Septic System
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1999 - Septic System
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Last modified
8/22/2023 4:50:47 PM
Creation date
1/17/2020 8:52:38 AM
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Template:
x Address Old
House Number
2845
Street Name
Wear
Street Type
Circle
Address
2845 Wear Circle
Document Type
Septic
PIN
3311823340009
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Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> I A. FLOWEstia„wa S4wue Flows 1m C 13oo per ay <br /> rOk <br /> Estimated Go 0 gpdr, •')I01 moo° mem •'?ve <br /> or measured -- x 1.5 = -' gpd. se.. <br /> 2 300 225 ISO ut, <br /> 3 450 300 211 a�e <br /> B. SEPTIC TANK LIQUID VOLUMES 4 50 375 256 in <br /> - /0 0 o gallons525 332 Tsm L <br /> ! 7 105 603 370 <br /> 1 1 1 1203 675 404 cam <br /> C. SOILS (refer to site evaluation) o L1 ,, -` 0$ <br /> .(`r.•...1 <br /> 1. Depth to restricting layer= ;,4. i.-.a(2,inches - feet N....rd Weis..Livid -a �. ,I <br /> 2. Depth of percolation tests = <br /> a � <br /> inches t+.e .. cn.e "`',w <br /> ' VI°''' `', ' VI1asb' <br /> �o a se-KN Percolation rate mpi 231.'71� 1 '° <br /> 3. Texture ,.. 1500 mo 700° <br /> 4. Land slope L• % 7.1.w i000 1333 .000 <br /> • <br /> D. ROCK LAYER.DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer. A x30.83 = <br /> C.oO gpd x 0.83 sq. ft./gpd = L4 ft <br /> g sq. .+-io.2oSy2 <br /> 2. Select width of rock layer (max 10' if <120 mpi max 5') = /o ft. <br /> 3. Length of rock layer= area +width = . -;•, 'a1'•'«' rr - . <br /> s q. ft. + / ft. ,• .....,,.e.,....,r....,.,,�...a..A � <br /> • ,s-,--10 --Q-- - •r/- 4...'Fj'�-1 .''r •. )1K•f isauccein.tveNNf.1:I? <br /> Width /o • ft • -aper;cevaav • . <br /> <120mpi <10'. Lente -‹-c' ft <br /> >120mpi <5' <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; .59-2 sq. ft. x o <br /> ft. = 9 L1 cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> ..cu. ft. +27 = 1_cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; a ) cu. yd. x 1.4 <br /> ton/cu.yd. = tons. <br /> Aborption Wldth Stria;Table <br /> F. ABSORPTION WIDTH ., <br /> 1. Percolation rate in top 12 inches of soil is c,•r/ mpi e t Raulatum tea . > �e.1 ; <br /> Texture ��� Lo A-' at .emre r t..7e`nam <br /> hoer dam 0,1 Corn Saes 1.20 1.00 <br /> 0.1 b S Saod 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; G 5 Floe Saad o 2.52eo11S Lows 0.. <br /> L-!. gpd/ft2 16 so 30 Lazo 0.60 2.00 <br /> • 3110 45 S11*Loa= 0.50 2.40 <br /> 46:NO <br /> a 60 C1aq Lo.m 0.450.24 2.67 <br /> 1 a <br /> 3. Calculate adsorption width ratio by dividing rock layer s3°"°"'"i 120 a13' 020 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/f6+ •y gpd/ft2 = . a•1-E7 . <br /> 4. • Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a.v, x io ft= u .'? ft <br />
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