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• <br /> 1. . <br /> PUMP SELECTION PROCEDURE <br /> A. Determine'pump capacity: ' <br /> Gravity Distribution END PERFORATION OF A PERFORATED LATERAL <br /> 1. Minimum suggested is 600 gallons per hour(10 gpm)to stay ahead of Wase corer <br /> i . a <br /> water use rate. ' <br /> Topeoa 'i9 i. <br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 : <br /> � .'• ••r•..;;;i'.1, <br /> ;t!'rw..,;,. <br /> • '►1,' y,.. •of IieoNxtlle Fabrk far torr- <br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. :Loofa/Sand Layer o,;err I,a»car<..a <br /> ^1e.i1rZ•iitltTLt�tll•I Perta'•tlon trilled tforlronlolly <br /> Pressure Distribution • / • kilo •p Hear Top <br /> 3. a. Select number of perforated laterals k • Al Least 12•Io Edge <br /> �e PI of Rock Layero I Rac��,.b. Select perforation spacing= {: ::`' : : " er..1111601,•.,.„. <br /> ft. .•,9-.�"��' • Perforations Located of <br /> °'k� <br /> c. Subtract 2 ft.from the rock layer length. k.. Clean Sand Layer Bottom d Lateral <br /> Rock layejlenstlI-2 ft. ft. Orlglnal Soll Properly scarified <br /> Before Plackq Sand toyer <br /> d. Determine the number of spaces between perforations. <br /> Length perf.spacing= ft.+ ft.= spaces TABLE OF PERFORATION DISCHARGES IN GPM <br /> e. spaces+1= perforations/lateral <br /> . f. Multiply perforations per lateral by number of laterals to Head Perforation diameter(Inches) <br /> get total number of perforations. 'ix, tie <br /> >n r. x „n,.i= perforations. <br /> 1.Oa 0.56 0.74 <br /> 1.5 0.69 0.90 <br /> g. t x Rizigpm. 2.0b 0.80 1.04 <br /> 23 0.89 1.17 <br /> SELECTED PUMP CAPACITY . 3.0 0.98 1.28 <br /> gpm 4.0 1.13 1.47 <br /> 5.0 1.26 1.65 <br /> B.Determine head requirements: aUse 1.0 foot of head for residential systems. <br /> 1. Elevation difference between pump and point of discharge. bUse 2.0 feet of head for other establishments <br /> I feet <br /> 2. If pumping to a pressure distribution system,add five feet for pressure <br /> required at manifold <br /> feet <br /> 3. Friction lossPipe Length t • <br /> a. Enter friction loss table with gpm and pipe diameter. Point of Discharge <br /> Read friction loss in feet per 100 feet from table. <br /> 0.......„----------- <br /> F.L.= 1.65 ft./100 ft of pipe Elevation Difference <br /> b. Determine total pipe length from pump to discharge • Pump <br /> :point. Add 25 percent to pipe length for fitting . <br /> loss,or use a fitting loss chart. Equivalent pipe F-18b <br /> length-1.25 times pipe length= 1.5 inch 2.0 inch 3.0 inch <br /> 233 x 1.25= Zq I feetgpm Make tae per 100 ft of pipe <br /> c. Calculate total friction loss by multiplying 10 0.69 0.20 <br /> friction loss in ft/100 ft by equivalent pipe length. 12 0.96 0.28 <br /> Total friction loss= Zq i x 1.5'S +100= it feet 14 1.28 0.38 <br /> 63 0.48 <br /> 4. Total head required is the sum of elevation difference, 16 2 03 0.60 <br /> special head requirements,and total friction loss. 20 2.47 0.73 0.11 <br /> G 25 3.73 0.16 <br /> 13 + + H.5 30 5.23 1 0.23 <br /> 35 7.90 2.06 0.30 <br /> (1) (2) (3c) 40 11.07 2.64 0.39 <br /> L 45 14.73 3.28 0.48 <br /> TOTAL HEAD 11.,J feet 50 3.99 0.58 <br /> 55 4.76 0.70 <br /> 60 5.60 0.82 <br /> C. Pump selection <br /> 1. A pump must be selected to deliver at least 3O gpm (Step A) <br /> with at least 11.S feet of total head (Step B). <br />