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C.- t.•J <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW D-7 <br /> 6'OUgpd . . • <br /> Estimated (see pages D-7 or I-3, 4, 5) C n Q^ mimics": ►a:.T <br /> or measured gpd. �d(f °� <br /> ■o■u <br /> a 700 m 100 <br /> 100 700 tt0 ; ' <br /> B. SEPTIC TANK LIQUID,VOLUMES • "' <br /> �D ��nn <br /> P" `^'/_•v f 1100 - 100 770 <br /> -/o CIO gallons (see pages C-3 or C-5) Jp tt= • .T. =r <br /> �i,Z,��Qc:C C-3 -- . <br /> C. SOILS (refer to site evaluation) worm T.,= cu.cmik w aLlo>,0 <br /> 1. Depth to restricting layer = 2-91 3c.) inches ""I `""", <br /> ��� 1.10.0 11.40,04111, M.NOK <br /> 2. Depth of percolation tests a /oZ inches 001100 f.. 1110 <br /> 3. Percolation rate , 3) mpi a• 1N1 1100 <br /> 4. Land slope ••OR <br /> • ,:NT. ;we: <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83-s <br /> loco gpd x 0.83 sq. ft/gpd =`-1`i'_ sq. ft.4- /U uk z <br /> 2. Select width of rock layer (10 feet or less) = /0 ft. <br /> 3. Length of rock layer = area+ width = <br /> 5-50 sq. ft. + io ft. = 6-,5- ft. Rock Bed <br /> �•.. ' !•l•�•r.r•I•f.r 1•!•1.1.1.1.11 /o/ <br /> 1.1.1.ti.ti.ti•ti.1.t•ti.t•1.ti•1•ti•• <br /> r•r•r•r.f•r•r.� �•r•1.1•r•!•I1 � <br /> ` t.ti.ti.1.1.ti.y.ti.�.ti•ti.1.�.1.ti.%Width <br /> 5191. <br /> 1 1.r•I.t.1:I:f:1;I:r:1:r:I:I:I1 <br /> E. ROCK VOLUME �-- Len gth <br /> 1. . Multiply rock area by rock depth to get cubic feet of rock; ,55 <br /> 550 sq. ft. x /.d ft. .550 cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft/cu. yd. to get cubic yards; <br /> 550 cu. ft. + 27 =c9o,q cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> c?o, y cu. yd. x 1.4 ton/cu. yd. 9 tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is 3 / mpi E-16 <br /> 2. Select allowable soil loading rate from table on page E-16; ........,�....WOO eWWI MOM.a.•01 <br /> gpd/1 t2 r.••.•••• .rte..rl r <br /> 3. Calculate adsorption width ratio by dividing rock layer "1' '"" """ ' ��`" • <br /> - <br /> loading rate of 1.20 gpd/ft2 byallowable soil loading rate; 1 1„ I. ;" <br /> . 1. 1" 1. <br /> 1. .. 1." .." 1... f... <br /> 1.20 gpd/ft2+ O•S0 gpd/ft2 = n?, `/D . 1N •N ," '" <br /> .. ..tt ., 1.lf <br /> .1 1!. 1.21 .y. 1.N 1 N <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> cP, Li/0 x /0 ft = 2'7'1 ft <br />