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MOUND DESIGN WORKSHEET <br /> �• (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day I <br /> Estimated 49C)0) gpd (see pages D-7 or I-3, 4, 5) Number cgPd> <br /> of Type 1 Type II Type III Type <br /> or measured gpd x 1.5 = Bedrooms IV <br /> 4 2 300 225 180 <br /> B. SEPTIC TANK LIQUID VOLUMES 3 450 300 218 <br /> 4 600 375 256 altbe <br /> ues <br /> o9-/a9t>a�l: 4 / ../ , gallons (see pages C-3 or C-5) 5 750 450 294 in <br /> V 6 900 525 332 Tia I. <br /> 7 1050 600 370 m <br /> 8 1200 675 408 columns <br /> C. SOILS (refer to site evaluation) <br /> Septic Tank Capacities,in gallons <br /> 1. Depth to restricting layer = D inches Number of Minimum Liquid Liquid capacity with <br /> 2. Depth of percolation tests = / inches Itedrooms Capacity garbage disposal <br /> 3. Percolation rate 'y? m i 2orIeu 750 1125 <br /> C 3 or 4 1000 1500 <br /> 4. Land slope cr % , Of 6 <br /> 4 a8 or y l500 <br /> 2000 2250, <br /> over 9 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = <br /> Cer`)b. gpd x 0.83 sq. ft./gpd = Snnsq. ft. <br /> 2. Select width of rock layer (10 feet or less) = /D ft. <br /> 3. Length of rock layer = Area+ Width = <br /> cS"OD sq. ft. 4- /v ft. = c5t ft. Rock Bed <br /> :r:%:f:r:f:f:f:f:r:r:f:r:r:f:fl Width S10 f t. <br /> •f•••f�r:f:f'?�f•f•r•f�f• •r•tf•f:� <br /> E. ROCK VOLUME Length - i <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> sq. ft. x / ft. =St cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> RM. cu. ft. + 27= /9 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> /9 cu. yd. x 1.4 ton/cu. yd. = c2& tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is ' mpi Absorption Width Sizing Table <br /> Pe2. Select allowable soil loadingrate from table on page E-; in MinutesinRate Gallop Ratio of <br /> p g in per Soil Texture per day per Absorption width <br /> gpd/f t2 Inch(MPI) square foot to Rock Layer <br /> Width <br /> 3. Calculate adsorption width ratio by dividing rock layer Faster than 0.1• Coarse Sand <br /> 0.1 to 5 Sand 1.20 1.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 0.1 to 5** Fine Sand•• 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 1.20 gpd/ft2+ , 516-gpd/ft2= 07• . 7 . 161o30 Loans 0.60 2.tl1 <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> Check this value on page E-16. 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 4. Multiply adsorption width ratio by rock layer width to get Slo12eerthan Clay <br /> required adsorption width; <br /> c1/.(e? x /o ft = Z.7 f t <br />