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2010-00430 - new mound system
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2010-00430 - new mound system
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Last modified
8/22/2023 4:29:14 PM
Creation date
12/3/2019 2:12:33 PM
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Template:
x Address Old
House Number
4295
Street Name
Watertown
Street Type
Road
Address
4295 Watertown Road
Document Type
Septic
PIN
3111823130004
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. PRESSURE DISTRIBUTION SYSTEM Geotextue fabric <br /> 1. Select number of perforated laterals 3 f Quarter inch perforations spaced et 3" U <br /> 1 9..of rock <br /> 2. Select perforation spacing= 3 ft <br /> Perf Sizing 3/16"-1/4" <br /> 3. Since perforations should not be placed closer than 1. foot to <br /> Perf Spacing 15 <br /> the edge of the rock layer(see diagram),subtract 2 feet from <br /> the rock layer length. E-4: f1 riMUM allowable neer of 1/4-inch perforations <br /> per lateral to guarantee<10%discharge variation <br /> 41 -2 ft = 3/ ft <br /> Rock layer length perforation <br /> spacing <br /> 4. Determine the number of spaces between perforations. (feet) 1 inch 1.25 inch 1.5 inch 20 inch <br /> Divide the length(3)by perforation spacing(2)and round <br /> down to nearest whole number. 25 8 14 1 28 <br /> Perforation spacing= 3 ft=3c/ ft= / 3 spaces 3.0 8 13 26 <br /> 3.3 7 12 16 25 <br /> 5. Number of perforations is equal to one plus the number of 4.0 7 11 15 23 <br /> perforation spaces(4). Check figure E-4 to assure the number of 5.0 6 10 14 22 <br /> perforations per lateral guarantees <10%discharge variation. <br /> 13 spaces+ 1 = /4 perforations/lateral E-6: Perforation Discharge in gpm <br /> 6. A. Total number of perforations= perforations per lateral(5) perforation diameter <br /> times number of laterals (1) head (nches)(feet) 1/8 3/16 7/32 1/4 <br /> /7 perfs/tat x -3 lat. 112. perforations 1.00 0.18 0.42 0.56 0.74 <br /> B. Calculate the square footage per perforation. 2.0b 0.26 0.59 0.80 1.04 <br /> Should be 6-10 sqft/perf.Does not apply to at-grades. 5.0 0.41 0.94 1.26 l.b5 <br /> Rock bed area= rock width(ft)x rock length(ft) <br /> /8 ft x 41 1 ft= 1-11 0 sqft O Use 1.0 foot for single-family homes. <br /> Square foot per perforation=Rock bed area=number of perfs(6) b use 2.0 feet for anything else. <br /> 41 f 0 sqft_ 42 perfs= '-7( sqft/perf SWOFOLD LOCATED AT OM OF DISTRIBUTION SYSTEM <br /> 7. Determine required flow rate by multiplying the total number of <br /> perforations(6A) by flow per perforation(see figure E-6) <br /> Z perfs x r 74 gpm/perfs= 3) gPm <br /> A <br /> 8. If laterals are connected to header pipe as shown on upper / l"""'rr: -� <br /> example,to select minimum required lateral diameter;enter - cam" <br /> figure E-4 with perforation spacing(2)and number of perforations \,-- -- <br /> per <br /> ,--/per lateral(5) Select minimum diameter for l..r";,,ES �,� FOR <br /> perforated lateral= inches. ,O�,,,IO 11.6,4..0 <br /> 9. If perforated lateral system is attached to manifold pipe nearv� x,�, ° <br /> the center,lower diagram,perforated lateral length(3)and r . <br /> number of perforations per lateral(5)will be approximately one `--urt,.:�.e.,d- - <br /> half of that in step 8. Using these values,select minimum m-2.0-4 <br /> diameter for perforated lateral= inches. `��. ..,rte <br /> I hereby certify t I have completed this work in accordance with applicable ordinances, rules and laws. <br /> & y 4- (signature) (license#) -5--3--/e) (date) <br />
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