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4220 Watertown Road - 31-118-23-13-0012
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Septic System Approval
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Last modified
8/22/2023 4:29:17 PM
Creation date
12/3/2019 12:48:31 PM
Metadata
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Template:
x Address Old
House Number
4220
Street Name
Watertown
Street Type
Road
Address
4220 Watertown Road
Document Type
Septic
PIN
3111823130012
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Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated scot`.Flows In Wow per <br /> Estimated kSO gpd aea7,4,41 TYPO Thy ra <br /> or measured x 1.5 =. gpd. Bedrooms <br /> 2 303 � <br /> i1b0a be <br /> B. SEPTIC TANK LIQUID VOLUMES a� <br /> 4 d00 373 256 nit <br /> 3 750 450 294 bt <br /> ), /0 0 gallons 6 900 525 332 7 1050 600 370 <br /> I 1 1203 675 408cet <br /> C. SOILS (refer to site evaluation) ''4rI,-L n <br /> 114set TN*call...04w la V.04..41 <br /> 1. Depth to restricting layer=),4)3°+-3� inches feet UT44 a <br /> iM 114.0 nr O a w rna a+r <br /> 2. Depth of percolation tests= I a inches "A lam <br /> 3. Texture w\ Percolation rate I 'z mpi 2Ms' 1002 112.21200 120202 <br /> 2 w 6 1500 2250 500 <br /> 4. Land slope 1 % ''t"' t020 2000 .00 <br /> • <br /> D. ROCK LAYER,DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer. A x 0.83 = <br /> _LL-____.:(-) gpd x 0.83 sq. ft./gpd = .-<=' sq. ft. )00-,., Lpo r'. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = (n ft. <br /> 3. Length of rock layer=area+width = j �q + ft. ft. Wtir.41:-, <br /> � ;0 3 . ft. "' X11 SL+!'t: ;t:�_vr.K•I, x.e-n•i.rtNotsc lze. Nei? <br /> Width /o ft 44/.,w7 r:rra;',--unP,vt yr irri 1st* <br /> • <120mpi <10' Length 41 ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; L+Jo sq. ft. x /,o. <br /> ft. = UFLu cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> C cu. ft. +27= ../_- cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;...L,... cu. yd. x 1.4 <br /> ton/cu.yd. = tons. <br /> F. ABSORPTION WIDTH Absorption Width Striag Table <br /> 1. Percolation rate in top 12 inches of soil is 1t3,2 mpi Palmlike a11om R,doofAbs <br /> G LA'-r 0 4\v o M1ou p�►Ixb Soil Tsz per pa eov <br /> Texture rlf <br /> h. .m.e 0,1 Cormed 1.20 1.00 <br /> 0.1 1! S.Seed 1.20 1.00 <br /> 2. Select allowable soil loadingrate from table; 0.115 Flee Stud 0.60 2.00 <br /> 6113 body Ler+► 0.79 1.52 <br /> _) d/ft2 160 Loam 0.60 2,00 <br /> -- or 13 31143 SIk Lamm 030 2.40 <br /> 46160 Grp bots 0.43 2.67 <br /> 0.24 3. Calculate adsorption width ratio by dividing rock layer s'°"'"t"'120 Cliv 0.20 6:00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2+.;: -gpd/ft= •C/7 <br /> 4. ' Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a.o' x ft = 2- ft <br />
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